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kenny6666 [7]
3 years ago
12

Suppose f(x)=x^2. Find the graph of f(x+2). Ive gone through the tutorial if someone could explain it that be extremely helpful.

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0
Substitute the value in for x and evaluate. 

x^2+4x+4
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You are dealt one card from a 52 card deck. Then the card is replaced in the deck, the deck is shuffled, and you draw again. Fin
AlladinOne [14]

Answer:

3/52

Step-by-step explanation:

The picture card are j,q k  and there are 4 of each so there are 12 picture cards

P( picture card) = picture card/ total

                          12/52 = 3/13

Then replace the card

There are 13 clubs

P( club) = club/ total

               13/52 = 1/4

P(picture,replace,club) = 3/13*1/4 = 3/52

7 0
3 years ago
Help me with differentation and integration please!!
Marina86 [1]

Answer:

See below

Step-by-step explanation:

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

Recall

\dfrac{d}{dx}\tan x=\sec^2

Using the chain rule

\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}

such that u = \tan x

we can get a general formulation for

y = \tan^n x

Considering the power rule

\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}

we have

\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x

therefore,

\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x

Now, once

\sec^2 x - 1= \tan^2x

we have

3\tan^2x \sec^2x =  3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x

Hence, we showed

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

================================================

For the integration,

$\int \sec^4 x\, dx $

considering the previous part, we will use the identity

\boxed{\sec^2 x - 1= \tan^2x}

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx $

Considering u = \tan x

and then du=\sec^2x\ dx

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx  = \dfrac{\tan^3 x}{3}+\tan x + C }$

6 0
3 years ago
What is the formula for volume of a square?
12345 [234]

Volume is measured of the objects which are three-dimensional .. And square is just a shape , hence it doesn't have any formula for volume .
.
If you were tryna ask about cube , the formula for cube is s^3
Where s is the side of the cube

3 0
4 years ago
Substitute 7x+2y = -14,x+y = 8
AysviL [449]
From second equation  y = 8 - x so

7x + 2(8 - x) = -14
5x = -14 - 16 = -30
x = -6

and y = 8 - -6 = 14

Answer x=-6,y=14
3 0
3 years ago
Suppose that you pick a bit string from the set of all bit strings of length ten. Find the probability that a) the bit string ha
emmasim [6.3K]

Answer:

  • 45/1024
  • 1/4
  • 15/128
  • 193/512
  • 9/512

Step-by-step explanation:

There are 2^10 = 1024 bit strings of length 10.

a) There are 10C2 = 45 ways to have exactly two 1-bits in 10 bits

  p(2 1-bits) = 45/1024

__

b) Of the four (4) possibilities for beginning and ending bits (00, 01, 11, 10), exactly one (1) of those is 00.

  p(b0=0 & b9=0) = 1/4

__

c) There are 10C7 = 120 ways to have seven 1-bits in the bit string.

  p(7 1-bits) = 120/1024 = 15/128

__

d) ∑10Ck {for k=0 to 4} = 386 is the total of the number of ways to have 0, 1, 2, 3, or 4 1-bits in the string. If there are more than that, there won't be more 0-bits than 1-bits

  p(more 0 bits) = 386/1024 = 193/512

__

e) The string will have two 1-bits if it starts with 1 and there is a single 1-bit among the other 9 bits. There are 9 ways that can happen, among the 512 ways to have 9 remaining bits.

  p(2 1-bits | first is a 1-bit) = 9/512

6 0
3 years ago
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