anything
Explanation:
I know what to say this time
A software-based <u>Firewall</u> is dedicated to examining and blocking internet traffic.
Answer:
Neither confirm nor deny the information is classified.
Explanation:
This action is taken because if you answer that the information is classified, more questions will arise about why it is classified thus leaving you in an awkward situation to respond (since it is classified by something).
In the event that you answer that it is not classified, it also gives rise to the reason that the information is not of simple access also exposing you to answering more questions and having to release the confidential information.
By denying both confidentiality and non-confidentiality, you refer to ignorance of the subject by avoiding further questions about such information on the web.
Answer:
- import math
-
- def standard_deviation(aList):
- sum = 0
- for x in aList:
- sum += x
-
- mean = sum / float(len(aList))
-
- sumDe = 0
-
- for x in aList:
- sumDe += (x - mean) * (x - mean)
-
- variance = sumDe / float(len(aList))
- SD = math.sqrt(variance)
-
- return SD
-
- print(standard_deviation([3,6, 7, 9, 12, 17]))
Explanation:
The solution code is written in Python 3.
Firstly, we need to import math module (Line 1).
Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).
We can test the function using a sample list (Line 20) and we shall get 4.509249752822894
If we pass an empty list, a ZeroDivisionError exception will be raised.
