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3 years ago

What's the 16-bit hexadecimal representation of the signed decimal integer, -331? Answeers?

Computers and Technology

1 answer:

disa [49]3 years ago

6 0

Solution:

The 16-bit hexadecimal representation of the signed decimal integer -331 is:

-[3*10^2+3*10^1+1*10^0]

This is the required answer.

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You have used loops for repetitive processes.

zzz [600]

Answer:

for

Explanation:

because:

IF = conditional
WHILE = conditional
DO = isn't a loop function

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3 years ago

In this lab, you complete a prewritten Python program for a carpenter who creates personalized house signs. The program is suppo

ivolga24 [154]

Using the computer language in python to write a function code that personalized house signs

<h3>Writting the code in python:</h3>

#Assign varibles

charge = 0.00

numChars = 8

color = "gold"

woodType = "oak"

#Checking for number of characters

if numChars > 5:

charge = 35 + (numChars-5)*4

elif numChars > 0:

charge = 35

#Checking wood type

if woodType == "oak":

charge += 20

#Checking for color

if color == "gold":

charge += 15

#Print output

print("The charge for this sign is $"+str(charge)+".")

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5 0

2 years ago

1. Write programming code in C++ for school-based grading system. The program should accept the Subject and the number of studen

satela [25.4K]

In this program, I am using the school-based grading system and the program should accept the subject and the number of students.

Program approach:-

Using the necessary header file.
Using the standard I/O namespace function.
Define the main function.
Declare the variable.
Display enter obtain marks in 5 subjects.
Return the value.

Program:-

//header file

#include<iostream>

//using namespace

using namespace std;

//main method

int main()

{

//declare variable

int j;

float mark, sum=0, a;

//display enter obtain marks in 5 subjects

cout<<"Enter Marks obtained in 5 Subjects: ";

for(j=0; j<5; j++)

{

cin>>mark;

sum = sum+mark;

}

a = sum/5;

//display grade

cout<<"\nGrade = ";

if(a>=91 && a<=100)

//display a1

cout<<"a1";

else if(a>=81 && a<91)

//display a2

cout<<"a2";

else if(a>=71 && a<81)

cout<<"b1";

else if(a>=61 && a<71)

cout<<"b2";

else if(a>=51 && a<61)

//display c1

cout<<"c1";

else if(a>=41 && a<51)

//display c2

cout<<"c2";

else if(a>=33 && a<41)

//display d

cout<<"d";

else if(a>=21 && a<33)

//display e1

cout<<"e1";

else if(a>=0 && a<21)

//display e2

cout<<"e2";

else

//display invalid

cout<<"Invalid!";

cout<<endl;

//return the value

return 0;

}

Learn more grading system

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7 0

3 years ago

Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o

masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

number = random.randint(0,9)

if number == 0:

count0 = count0 + 1

if number == 1:

count1 = count1 + 1

if number == 2:

count2 = count2 + 1

if number == 3:

count3 = count3 + 1

if number == 4:

count4 = count4 + 1

if number == 0:

count5 = count5 + 1

if number == 6:

count6 = count6 + 1

if number == 7:

count7 = count7 + 1

if number == 0:

count8 = count8 + 1

if number == 9:

count9 = count9 + 1

i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize i to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

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3 years ago

Meaning of sperm count

yulyashka [42]

a measure of the number of spermatozoa per ejaculation or per measured amount of semen, used as an indication of a man's fertility.

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3 years ago

Read 2 more answers