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2 years ago

I don't understand can someone explain

Mathematics

1 answer:

Tomtit [17]2 years ago

3 0

This is a function when u have f(n) u plug in the number for example 1 because the number -13 is the first number in the sequence

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(2x-20) + 86 what is the the value of x

julsineya [31]

When (2x-20)＋86＝0
2x-20＝-86
2x＝-46
x＝-23

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3 years ago

If the height of a right triangle is 24 inches and the the area of the triangle is 120 square inches, what is the length of the

Rus_ich [418]

(120×2)/24 = 10inches

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3 years ago

Which Kind of Triangle is Shown?

Alexus [3.1K]

Hi! The answer is right scalene triangle! Hope this is right! :)

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1 year ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

2 years ago

The area of triangle ABC is 1.89 square feet. The measure of side c is ______.

Feliz [49]

we are given

Area is 1.89

$A=40$

$b=2.8$

now, we can use area formula

$A=\frac{1}{2} c*b*sin(A)$

$1.89=\frac{1}{2} *c*2.8*sin(40)$

now, we can solve for c

we will get

$c=2.10023$ .............Answer

7 0

3 years ago