Question

Find the distance between (3,5) and (7,-3). **(round to the nearest tenth.)

Answer 1

Answer:

The answer is

8.9 units

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{( {x1 - x2})^{2} + ({y1 - y2})^{2} }$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3,5)and (7,-3)

The distance between them is

$d = \sqrt{( {3 - 7})^{2} + ({5 + 3})^{2} } \\ = \sqrt{ ({ - 4})^{2} + {8}^{2} } \\ = \sqrt{16 + 64} \\ = \sqrt{80} \\ =4 \sqrt{5} \\ \: \: \: \: = 8.9442$

We have the final answer as

8.9 units to the nearest tenth

Hope this helps you

Answer 2

Step-by-step explanation:

√(7-3)^2+(-8)^2

√16+64

√80

8.94