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DiKsa [7]
3 years ago
13

What's the answer to 16-12+12x17

Mathematics
2 answers:
daser333 [38]3 years ago
4 0
16-12+12x17= 208 u should use a calcuator
Sav [38]3 years ago
4 0
16-12+12×17,according to pemdas
P
E
M
D
A
S
the answer is 208
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1. Solve the equation.
Keith_Richards [23]

Answer:

1. -3

2. -12

3. 20

4. -15

5. 6

6. -15w+5

7. 10

8. C<-26

9.p> -40

10. P> 16

Step-by-step explanation:

~ -9p -17 = 10

-9p = 27

P = -3

~ x/4 -5 = -8

x/4 = -3

x = -12

~ p/5 +6 =10

p/5 = 4

p = 20

~ -2(m-30) =-6m

-2m+60=-6m

4m = -60

m = -15

~ 3n +2=8+2n

n = 6

8 0
3 years ago
You have $270 in your bank account. You plan to save $80 from your paycheck each week. Which graph shows your bank account balan
elixir [45]
Y=80x+270
If you want to know how to do it just let me know
7 0
3 years ago
Read 2 more answers
Find the exact value of secθ if cscθ=-4/3 and the terminal side of θ lies in Quadrant III.
Anton [14]
Quadrant is III so, sign would be negative for Sec.
Now, we know, csc = H / P
So, H = 4, P = 3
Calculate for B, 
B² = H² - P²
B² = 4² - 3²
B² = 16 - 9
B = √7

We know, sec Ф = H / B = 4 / √7
We can write it as: -4√7 / 7  [ -ve sign for 3rd quadrant ]

In short, Your Answer would be Option B

Hope this helps!
6 0
3 years ago
What does the fundamental theorem of algebra illustrate?
UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

a = 2

b = -4

c = -1

If the roots are x_{1} and x_{2}, then

x_{1} = \frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                       = \frac{4 +\sqrt{24}}{4}

                       = \frac{2+\sqrt{6} }{2}

x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                        = \frac{4 +\sqrt{8}}{4}

                        = \frac{2-\sqrt{6} }{2}

These are the two roots of the equation.

6 0
3 years ago
Angles 1 and 2 or complementary. If &lt;1 measures 29.6°, then what is the measure of &lt;2?
Sever21 [200]
Complementary angles add up to 90 degrees so if one is 29.6 degrees you subtract 29.6 from 90 so the answer is 60.4 degrees.
8 0
3 years ago
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