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schepotkina [342]
3 years ago
10

Hello! Can someone help me with this, please?

Mathematics
2 answers:
marysya [2.9K]3 years ago
6 0
5.5 ft have a good day
Trava [24]3 years ago
5 0

Answer:

5.5 ft

Hope this helped!

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Marianna [84]

Answer:True, False, False, True

Step-by-step explanation:

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3 years ago
A regular hexagon has a radius of 20 in. What is the approximate area of the hexagon?
lawyer [7]

Answer:

1,038 in2

Step-by-step explanation:

In a regular hexagon, the radius and side length are equal in length... That makes the answer 1038 in.2 correct?

8 0
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A number, added to its three quarters, is equal to its double decreased by 6. What is the number
faust18 [17]

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9

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i hope this is helpful........

7 0
3 years ago
The area of a triangle is 20 cm², and the
grandymaker [24]

Answer:

Heavenly,  we need the forumula for the area of a triangle, do you know it?

Step-by-step explanation:

Area of a triangle is (1/2 ) * B*H

where B = base

H = height

then

A = 1/2* B * H

A is given to be 20

B = b

H = b+4

plug all those into the formula,

20 = (1/2)*b*(b+4)

use your algebra skillz  :P

20 = 1/2 *( b^{2} + 4b)

20*2 = b^{2} + 4b

40 = b^{2} + 4b

0 = b^{2} + 4b-40

rewrite the above so it's in x format

x^{2} + 4x -40 = 0

use the quadratic formula to find  x  , and for our problem, remember that x represents the base,  or b,  but don't mix it up with the b in the quadatic fomula,  with the b of the triangle, which is the base,  they are differnt "b"s   :P

X = (b±\sqrt{b^{2}-4*a*c } ) / 2*a

a = 1

b = 4

c = -40

x = (4±\sqrt{4^{2}-4*1*(-40) }  ) /2*1

x = ( 4±\sqrt{16+160} ) / 2

x = (4±\sqrt{176} ) / 2

x = (4±13.266499)/2

x= 2±6.633249

x = 2 + 6.633249 = 8.633

b= 8.633 cm

5 0
2 years ago
How do you find the surface area
WITCHER [35]

Answer:

It depends on what shape you have. Here are some formulas for different shapes.

Step-by-step explanation:

Rectangular prism: 2lw + 2lh + 2wh

Cylinder: 2 pi <em>r</em>² + 2 pi <em>rh</em>

Sphere: 4 pi <em>r</em>²

Cone: pi <em>r</em>² + pi <em>rl</em>

Square-based pyrimid: 1/2<em>lp</em> +<em>B</em>

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I hope this helps!

3 0
3 years ago
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