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3 years ago

Find a equation for the slope 3/2 and Y intercept -1

Mathematics

1 answer:

Mashcka [7]3 years ago

5 0

Answer:

$\large\boxed{y=\dfrac{3}{2}x-1}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have

$m=\dfrac{3}{2},\ b=-1$

Substitute:

$y=\dfrac{3}{2}x+(-1)=\dfrac{3}{2}x-1$

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HELPPP FOR 25 POINTS

MrRa [10]

Answer:

X/15 = 32/20

x = 24 ft

Step-by-step explanation:

X/15 = 32/20

x = 24 ft

4 0

2 years ago

Find the sum: (3x2 + 5x − 8) + (5x2 − 13x − 5)

musickatia [10]

Answer:

$(3x^2+5x-8)+(5x^2-13x-5)=8x^2-8x-13$

Step-by-step explanation:

The given polynomials are,

$3x^2+5x-8,5x^2-13x-5$

In polynomial addition and subtraction only like terms can be added or subtracted.

So,

$=(3x^2+5x-8)+(5x^2-13x-5)$

$=3x^2+5x-8+5x^2-13x-5$

$=3x^2+5x^2+5x-13x-8-5$

$=8x^2-8x-13$

7 0

2 years ago

Read 2 more answers

Perform the indicated operation 7+9+(4) 20 20 O12 O-12

Ivahew [28]

The answer would be 20.

How?

7 + 9 = 16

16 + 4 = 20

7 0

3 years ago

What is the solution to the following system? 3x+3y=10 -9x-9y=-30

Degger [83]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We have the equations,

1. 3x+3y=10

2. -9x-9y= -30

Now, if we multiply equation 1 with -3, we will obtain equation 2.

i.e. -3×(3x+3y)= -3×10

i.e. -9x-9= -30

So, we see that both the equations are same.

The equation 3x+3y=10 will have solution for many values of x and y.

Hence, the system will have infinite number of solutions.

4 0

2 years ago

Read 2 more answers

If a₁ = 4 and an = 5an-1 then find the value of a5.

igor_vitrenko [27]

The value of $a_{5}$ is 2500, when $a_{1}=4$ and $5a_{n-1}$ .

Given that, $a_{1}=4$ and $5a_{n-1}$ .

We need to find the value of $a_{5}$ .

<h3>What is an arithmetic sequence?</h3>

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of $a_{5}$ :

$a_{2} =5a_{2-1}=5a_{1}=5 \times4=20$

$a_{3} =5a_{3-1}=5a_{2}=5 \times20=100$

$a_{4} =5a_{4-1}=5a_{3}=5 \times100=500$

$a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500$

Therefore, the value of $a_{5}$ is 2500.

To learn more about arithmetic sequence visit:

brainly.com/question/15412619.

#SPJ1

5 0

2 years ago