You can use (-25,-5) it fits the equation and it’s in the solution set
Answer:
Step-by-step explanation:
If the price is supposed to be dropping with each year, maybe your year/price chart would reflect that. Seems to me that the price rose between 2015 and 2016 and even by 2017 the value was still higher than it was in 2015.
I have no way of knowing how to fix this.
Let's ASSUME that the 2015 price was $71,445 and that the 2016 and 2017 prices are valid.
the decrease between 2015 and 2016 is (71445 - 68640) / 71445 = 0.03926
or 3.926%
the decrease between 2016 and 2017 is (68640 - 65945)/68640 = 0.03926
or 3.926%
so the price each year after new is
p = 71445(1 - 0.03926)ⁿ
or
71445(0.96074)ⁿ
where n is the number of years.
To get the monthly version, we divide the decrease by 12
p = 71445(1 - 0.03926/12)ˣ
or
p = 71445(1 - 0.00327)ˣ
or
p = 71445(0.99673)ˣ
where x is the number of months since new.
This may not be your exact answer, but the same method can be used if you get real numbers.
The null hypothesis suggests that the two samples come from the same distribution(s), and the experimental hypothesis suggests that the two samples come from different distribution(s).
Answer: a) 236,000.
b) 2021
Step-by-step explanation:
Given : Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by 
(1)
where t = 0 corresponds to 1980.
Then , for 2009
t= 2009-1980=29
a. ⇒The population of Phoenix in 2009 = 
Hence, the population of Orlando in 2009 was about 236,000.
b) Substitute p= 300 in (1) , we get
(Divide both sides by 130)
Taking Natural log on both sides,
Hence, The year Orlando will have a population of 300,000 =1980+41 =2021
15 plus 15 is going to be 30
