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2 years ago

8

About 36,100,000 households in the U.S. have cats and about 43,300,000 households have dogs. About how may more households dogs

and cats

1 answer:

Svetllana [295]2 years ago

5 0

Theres about a 7,200,000 difference between household dogs vs household cats

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Using Unit Rates to compare Ratios continued

nasty-shy [4]

Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball $75$ times for $550$ yards, and Pete has $42$ carries for $380$ yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon $=550\text{yards}$

No. of times ball carried by Brandon $=75\text{ times}$

Average yards per carry for Brandon $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{550}{75}$

$=\frac{22}{3}\text{ yards per carry}$

$=7.33\text{ yards per carry}$

Total yards traveled by Pete $=380\text{ yards}$

No. of times ball carried by Pete $=42\text{ times}$

Average yards per carry for Pete $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{380}{42}$

≅ $9\text{ yards per carry}$

As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.

4 0

3 years ago

If x was 4, what is the value of 4x + 3

Gemiola [76]

Answer:

19

Step-by-step explanation:

4(4)+3

16+3=19

3 0

1 year ago

Read 2 more answers

Find that median 169, 72, 161, 322, 56, 145, 64,64, 80, 288, 95, 97, 209,209,48

Alexus [3.1K]

Answer:

97

Step-by-step explanation:

The number in the middle is 97

4 0

2 years ago

Read 2 more answers

Adecco Workplace Insights Survey sampled men and women workers and asked if they expected to get a raise or promotion this year

Mumz [18]

Answer:

Yes

Step-by-step explanation:

Let p1 represent proportion of women and p2 proportion of men. The null and alternative hypothesis will be as follows

Null hypothesis

$H_o$ =p2-p1 ≤0

Alternative hypothesis

$H_a$ =p2-p1>0

Sample proportion of women, p1=74/200=0.37

Sample proportion of men is p2=104/200=0.52

Level of significance is 0.01

Pooled proportion= $\frac {104+74}{200+200}=0.445$

Test statistic

$z=\frac {(0.52-0.37)-0}{0.445(1-0.445)*\sqrt{(1/200+1/200)}}=6.9124$

p-value=P(Z≥z)=P(Z≥6.9124)=P(Z≤-6.9124)=0

Since the value of p is less than 0.01, we reject null hypothesis. There’s sufficient evidence that a greater proportion of men is expecting to get a raise

6 0

3 years ago

The volume of construction work was increased by 60% but the productivity of labor increased by only 25%. By what percent must t

Stolb23 [73]

Answer: The answer is 28%.

Step-by-step explanation: Given that the volume of construction work was increased by 60% and the productivity of labour increased by 25% only. We are to find the percentage by which the number of workers must increase to complete the in time.

Let 'V' be the volume of construction work, 'p' be the productivity of labour, 'n' be the number of workers, and 'x' be the percentage by which the number of workers must increase.

According to the question, we have

$V=r\times n,\\\\\dfrac{8}{5}V=\dfrac{5}{4}r\times n(1+x).$

Dividing the second equation by the first equation, we have

$\dfrac{\frac{8}{5}V}{V}=\dfrac{\frac{5}{4}nr(1+x)}{nr}\\\\\Rightarrow \dfrac{8}{5}=\dfrac{5}{4}(1+x)\\\\\Rightarrow 1+x=\dfrac{32}{25}\\\\\Rightarrow x=\dfrac{7}{25}=0.28.$ .

Thus, the required percentage of workers that must increase in order to complete the work in time as scheduled originally is 28%.

5 0

2 years ago