Answer: Answer is D, if I'm not mistaking
Step-by-step explanation:
sorry if im wrong.
See the picture attached to better understand the problem
we know that
90°+∠BAC=180°------> by supplementary angles
∠BAC=90°
125°+∠ABC=180° -----> by supplementary angles
∠ABC=55°
∠BAC+∠ABC+p=180----> <span>sum of the internal angles of a triangle is 180 degrees
</span>p=180-90-55-----> p=35°
the answer isp=35°
To do this without a calculator, it may be easier to break the number into smaller parts.
420 * 6
= (400 * 6) + (20 * 6)
= 2400 + 120
= 2520
Hope this helps! :)
Step-by-step explanation:
![\underline{\large{ \tt{G \: I \: V \: E \: N}}} :](https://tex.z-dn.net/?f=%20%20%5Cunderline%7B%5Clarge%7B%20%5Ctt%7BG%20%5C%3A%20I%20%5C%3A%20V%20%5C%3A%20E%20%5C%3A%20N%7D%7D%7D%20%3A%20)
- Line a & b are parallel
- m ∠ 8 = 150 °
![\underline{ \large{ \tt{T \: O\: \: F \: I \: N \:D}}} :](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BT%20%5C%3A%20O%5C%3A%20%20%5C%3A%20F%20%5C%3A%20I%20%5C%3A%20N%20%5C%3AD%7D%7D%7D%20%3A%20)
![\underline{ \large{ \tt{S\: O \:L \: U \: T \: I \: O \: N}}} :](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BS%5C%3A%20O%20%5C%3AL%20%5C%3A%20U%20%5C%3A%20T%20%5C%3A%20I%20%5C%3A%20O%20%5C%3A%20N%7D%7D%7D%20%3A%20)
[ Sum of co-interior angles ]
⤑ ![\large{ \tt{150 \degree \: + m \: \angle \: 2}} = 180 \degree](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7B150%20%5Cdegree%20%5C%3A%20%20%2B%20m%20%20%5C%3A%20%5Cangle%20%5C%3A%202%7D%7D%20%3D%20180%20%5Cdegree)
⤑ ![\large{ \tt{m \angle \: 2 \: = \: 180 \degree - 150 \degree}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7Bm%20%5Cangle%20%5C%3A%202%20%5C%3A%20%20%3D%20%20%5C%3A%20180%20%5Cdegree%20-%20150%20%5Cdegree%7D%7D)
⤑ ![\large{ \tt{m \: \angle \: 2 \: = \bold{ \tt{30 \degree}}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctt%7Bm%20%20%5C%3A%20%5Cangle%20%5C%3A%202%20%5C%3A%20%20%3D%20%20%5Cbold%7B%20%5Ctt%7B30%20%5Cdegree%7D%7D%7D%7D)
![\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline{ \bold{ \tt{30 \degree}}}}}}}}](https://tex.z-dn.net/?f=%20%5Cred%7B%20%5Cboxed%7B%20%5Cboxed%7B%20%5Ctt%7BOur%20%5C%3A%20final%20%5C%3A%20answer%20%3A%20%20%5Cboxed%7B%20%5Cunderline%7B%20%5Cbold%7B%20%5Ctt%7B30%20%5Cdegree%7D%7D%7D%7D%7D%7D%7D%7D)
Hope I helped ! ♡
Have a wonderful day / night ! ツ
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Answer:
Step-by-step explanation: if there are 500 pieces of paper and the entire stack is 1.875 inches tall, you devide the total height by 500. I know Deigo is wrong because you can easily reverse check his work by multiplying 0.015 by the total number of papers 500 you will get 7.5 which is not the height of the stack
1.875/500=0.00375
each piece of paper is 0.00375