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BARSIC [14]
3 years ago
11

The distribution of the time it takes for different people to solve a certain crossword puzzle is strongly skewed to the right,

with a mean of 30 minutes and a standard deviation of 15 minutes. the distribution of z-scores for those times is
Mathematics
1 answer:
dezoksy [38]3 years ago
5 0
<span>Answer: Skewed to right with mean 0 and S.D. 1 Explanation: Let's assume the z-scores as a linear transformation. then z=(x-mean)/S.D. = (x-30)/15 z(mean) = (30-30)/15= 0 z(sigma) = 15/15 = 1 Note: Shape does not change.</span>
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Find the relationship between the number of movie tickets sold and number of available seats
densk [106]
The relationship is negative 4 
8 0
3 years ago
Suppose that g(x) = f(x + 8) + 4. Which statement best compares the graph of g(x) with the graph of f(x)?
UNO [17]
The graph of g(x) is the same as that of f(x), EXCEPT that the graph of f(x) has been translated 8 units to the left and 4 units up.
4 0
3 years ago
Line 2x-4y-7=0 meets the x axis at point (k,0). Find the value of k
kolbaska11 [484]
K=4
add seven on both sides
2x-4y=7
add 4y on both sides
2x=7+4y
divide 2 on both sides
x=7+4y/2
plug that into original equation
2(7+4y/2)-4y-7=0
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4 0
2 years ago
Which expression can be used to determine the length of segment AB? On a coordinate plane, triangle A B C has points (4, 3), (ne
JulijaS [17]

Answer:

StartRoot 2 squared + 6 squared EndRoot

Step-by-step explanation:

we have

A(4,3) and B(-2,1)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the given values

AB=\sqrt{(1-3)^{2}+(-2-4)^{2}}

AB=\sqrt{(-2)^{2}+(-6)^{2}}

AB=\sqrt{40}\ units

therefore

StartRoot 2 squared + 6 squared EndRoot

7 0
3 years ago
Read 2 more answers
Solve for h.
Luden [163]
Solving for h means we write the equation in such a way that h is isolated from other variables. It is done as follows: 

(P = mgh) 1/mg
P/mg = mgh/mg
h = P/mg

Therefore, the correct answer from the choices listed above is option C, h = p/mg.

Hope this answers the question. Have a nice day. 
4 0
2 years ago
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