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hodyreva [135]
3 years ago
8

Please help asap, will mark Brainliest xoxo

Mathematics
1 answer:
IgorC [24]3 years ago
3 0

Answer/Step-by-step explanation:

Given, b(x) = (\frac{6}{7})^{x}

The table for the function are:

When x = -2

b(-2) = (\frac{6}{7})^{-2}

b(-2) = \frac{1}{(\frac{6}{7})^{2}}

b(-2) = \frac{1}{(\frac{36}{49})}

b(-2) = 1*\frac{49}{36}

b(-2) = \frac{49}{36}

When x = -1

b(-1) = (\frac{6}{7})^{-1}

b(-1) = \frac{1}{(\frac{6}{7})}

b(-1) = 1*\frac{7}{6}

b(-2) = \frac{7}{6}

When x = 0

b(0) = (\frac{6}{7})^{0}

b(0) = \frac{6^0}{7^0}

b(0) = \frac{1}{1}

b(0) = 1

When x = 1

b(1) = (\frac{6}{7})^{1}

b(1) = \frac{6}{7}

When x = 2

b(2) = (\frac{6}{7})^{2}

b(2) = \frac{6^2}{7^2}

b(2) = \frac{36}{49}

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