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lora16 [44]
3 years ago
11

p: If every fourth card drawn is a spade, then 25% of the cards in a deck would be spades. If 25% of the cards in a deck are spa

des, then every fourth card drawn would be a spade. If every fourth card drawn isn’t a spade, then 25% of the cards in a deck aren’t spades. If 25% of the cards in a deck aren’t spades, then every fourth card drawn wouldn’t be a spade. If every fourth card drawn isn’t a spade, then 75% of the cards in a deck are spades.
Mathematics
1 answer:
Nikitich [7]3 years ago
3 0
NO....... It is 25% spades and 75% are not spades
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Which is a solution to (x - 2)(x + 10) = 13 ?
stiv31 [10]
The answer is:
x=3,-11
4 0
3 years ago
Read 2 more answers
(x-2)(x+2)(x²+4)-(x²+3)(x²-3)+2022
torisob [31]

The simplified form of the given expression is 2015

<h3>Simplifying expressions </h3>

The given expression is (x-2)(x+2)(x²+4)-(x²+3)(x²-3)+2022

The expression can be simplified as shown below

(x-2)(x+2)(x²+4) - (x²+3)(x²-3) + 2022

x(x+2)-2(x+2)(x²+4) - x²(x²-3) +3(x²-3) + 2022

(x²+2x-2x-4)(x²+4) - (x⁴-3x²+3x²-9) + 2022

(x²-4)(x²+4) - (x⁴-9) + 2022

x²(x²+4) -4(x²+4) - (x⁴-9) + 2022

(x⁴+4x²-4x²-16) - (x⁴-9) + 2022

(x⁴-16) - (x⁴-9) + 2022

x⁴ -16 -x⁴ +9 + 2022

x⁴ -x⁴ -16 +9 +2022

= 2015

Hence, the simplified expression is 2015

Learn more on Simplifying an expression here: brainly.com/question/723406

#SPJ1

3 0
2 years ago
Can someone please help me I really need help please help me
luda_lava [24]

Answer:

1080

Step-by-step explanation:

5 0
3 years ago
Plz help with this question
soldi70 [24.7K]
Somehow i got 2.5 guess i am wrong...
4 0
3 years ago
I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
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