It's not clear whether the problem is to:
(1) divide
by 
, or
(2) divide
by 
.
But with only two possible cases, that's not much work to do.
Synthetic division yields a quotient and remainder of
(see attachment for how the algorithm was carried out).
In the other case,
provided that
. Synthetic division can be used again here, but this is quite easy to deal with by just doing some easy manipulation of the numerator:
(also provided that
)
(1) divide
(2) divide
But with only two possible cases, that's not much work to do.
Synthetic division yields a quotient and remainder of
In the other case,
provided that
(also provided that