In a right triangle the sum of the squares of the lengths of two shorter sides is equal to the square of the length of the longest side.
a.
b.
c.
The answer is A and C.
a.
b.
c.
The answer is A and C.
How can I solve this??
1 answer:
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Answer:
<h3>A. </h3>- log
= log 3
- x³ log x = log 3
- 3x³ log x = 3 log 3
- x³ log x³ = log 3³
= 3³
- x³ = 3
- x =
- 4ˣ + 6ˣ = 9ˣ
- 2²ˣ + 2ˣ3ˣ = 3²ˣ
<u>Divide both sides by 2²ˣ</u>
- 1 + (3/2)ˣ = (3/2)²ˣ
<u>Substitute (3/2)ˣ = t</u>
- t² - t - 1 = 0
<u>Solve for t:</u>
- t = (1 ± √5)/2
<u>Positive root is considered as (3/2)ˣ can't be negative.</u>
- (3/2)ˣ = (1 + √5)/2
- x = log [(1 + √5)/2] / log (3/2)
- x = 1.18681439028