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2 years ago

A circle has a radius of 6. An arc in this circle has a central angle of 330

Mathematics

2 answers:

Strike441 [17]2 years ago

4 0

Answer: 11 pi

Step-by-step explanation: Found the answer of Khan Academy.

sashaice [31]2 years ago

3 0

Answer: $Arc\ lenght\approx34.55\ units$

Step-by-step explanation:

<h3> The complete exercise is: " A circle has a radius of 6. An arc in this circle has a central angle of 330 degrees. What is the arc length?"</h3><h3></h3>

To solve this exercise you need to use the following formula to find the Arc lenght:

$Arc\ lenght=2\pi r(\frac{C}{360})$

Where "C" is the central angle of the arc (in degrees) and "r" is the radius.

In this case, after analize the information given in the exercise, you can identify that the radius and the central angle in degrees, are:

$r=6\ units\\\\C=330$

Therefore, knowing these values, you can substitute them into the formula:

$Arc\ lenght=2\pi (6\ units)(\frac{330}{360})$

And finally,you must evaluate in order to find the Arc lenght.

You get that this is:

$Arc\ lenght=2\pi (6\ units)(\frac{11}{12})\\\\Arc\ lenght=11\pi \ units\\\\Arc\ lenght\approx34.55\ units$

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-4x - y = 24<br> Complete the missing value in the solution to the equation.<br> ( _,8)

Zinaida [17]

Answer:

(- 8, 8 )

Step-by-step explanation:

Given ( ?, 8 ) is a solution. To find x substitute y = 8 into the equation, then

- 4x - 8 = 24 ( add 8 to both sides )

- 4x = 32 ( divide both sides by - 4 )

x = - 8

Thus solution is (- 8, 8 )

5 0

2 years ago

Evaluate 8^<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7D" id="TexFormula1" title="\frac{5}{3}" alt="\frac{5}{3}" align

almond37 [142]

Answer:

Step-by-step explanation:

32 is the correct answer

6 0

2 years ago

Read 2 more answers

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

6 0

2 years ago

The manufacturer of an energy drink spends $1.20 to make each drink and sells them for two dollars the manufacturer also has fix

dimulka [17.4K]

Let X be the number of energy drinks sold.

The manufacturer of an energy drink spends $1.20 to make each drink and sells them for two dollars the manufacturer also has fixed cost each month of $8000.

The manufacturing cost for X energy drinks is

$1.20x$

Fixed cost is $8000.

Therefore, cost function is

$C(x)=1.20x+8000$

Selling price of each drink is $2.

Therefore, the revenue function is

$R(x)=2x$

Hence, the revenue function is

$R(x)=2x$

6 0

10 months ago

The equation of (0, 3 (4, 2)

marusya05 [52]

Answer:

4x+y=12

Step-by-step explanation:

its the only one that is positive

and this is guess so don’t hate me if its wrong

hope this is right

5 0

2 years ago