Answer:
What??
Step-by-step explanation:
Plz mark brainliest
Altho' I'm not using the fund. thm. of alg. specifically to determine the # of roots of 2x^2 + 4x + 7, polynomials of the nth degree all have n roots.
Completing the square: 2x^2 + 4x + 7
2(x^2 + 2x + 1 - 1) +7
2(x+1)^2 - 2 +7
2(x+1)^2 + 5
To solve for the roots, set the above = to 0 and solve for x:
2(x+1)^2 = -5 => (x+1)^2 = -5/2
x+1 = plus or minus sqrt (-5/2) => x+1 = plus or minus i*sqrt(5/2)
... and so on. As expected, this 2nd order poly has 2 roots. The roots in this case happen to be complex.
Answer:
2.33
Step-by-step explanation:
Answer:
9.4 units
Step-by-step explanation:
So first we need to create a right angled triangle so that we can use Pythagoras theorem.
The difference in y = 6 - 1 = 5
The difference in x = 5 - -3 = 8
Finding the length of line segment CD is like finding the magnitude or the hypotenuse. So:
CD² = 8² +5²
CD² = 64 + 25
CD² = 89²
CD = √89
CD = 9.4
Because we aren't given any units we leave it as 9.4 units or just 9.4
Answer:
you betta do ya best it might be 34
Step-by-step explanation: