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3 years ago

Can someone help me please???

Mathematics

1 answer:

Karolina [17]3 years ago

8 0

Answer:

Altitude of Equilateral Triangle h = (1/2) * √3 * a. Angles of Equilateral Triangle: A = B = C = 60° Sides of Equilateral Triangle: a = b = c.

Hope this helped!

If you would like me to simplify it a little let me know.

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Is This A Function?? Will Give Crown!!

Pepsi [2]

Answer:

yes it is a function

Step-by-step explanation:

7 0

3 years ago

Musah stands at the center of a rectangular field . He first takes 50 steps north, then 25 step west and finally 50 steps on a b

ElenaW [278]

Answer:

85.36 far north from the center

10.36 far east from the center

Step-by-step explanation:

The extra direction taken in the north side is x

X/sin(360-315)=50/sin 90

Sin 90= 1

X/sin 45= 50

X= sin45 *50

X= 0.7071*50

X= 35.355 steps

X= 35.36

Then the west direction traveled

West =√(50² - 35.355²)

West = √(2500-1249.6225)

West= √1250.3775

West= 35.36 steps

But this was taken in an opposite west direction

From the center

He is 35.36 +50

= 85.36 far north from the center

And

25-35.36=-10.36

10.36 far east from the center

3 0

4 years ago

2 sin x cos x = tan x

eimsori [14]

Answer:

If $sin x = 0$ we get $2 (0) (\pm1) = 0$ which is true. so we have a first set of solutions given by

$x= 0; x = \pi$ ;

Else, if $sin x \ne 0$ we can divide both sides by it and we get

$2 cos x = \frac 1 {cos x} \rightarrow 2cos^2x =1 \rightarrow cos^2x =\frac12\\cos x= \pm \frac{\sqrt2}2$

Which gives us a second set of solutions given by $x= \frac{\pi}4;x= \frac{3\pi}4; x= \frac{5\pi}4;x= \frac{7\pi}4$ ;

We can group all solutions (doesn't matter, but it's more elegant!) by writing

$x= k\frac{\pi}4; k\in \{0,1,3,4,5,7\}$

8 0

2 years ago

What is y when x=60 A) About 210 B) About 225 C) About 250 D) About 300

STALIN [3.7K]

Answer:

D) About 300

Step-by-step explanation:

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3 years ago

What is -3/5 x -10/21?

sammy [17]

The answer would be 2/7!

7 0

4 years ago

Can someone help me please???​

Can someone help me please???