Answer:
Given: PR=EF, QR=DE and PQ=FD
Now, In △PRQ and △DEF
PR=EF
QR=DE
PQ=FD
Thus, △PQR≅△FDE (SSS rule).
Option C:
x = 90°
Solution:
Given equation:

<u>To find the degree:</u>

Subtract 1 + cos²x from both sides.

Using the trigonometric identity:




Let sin x = u

Factor the quadratic equation.

u + 2 = 0, u – 1 = 0
u = –2, u = 1
That is sin x = –2, sin x = 1
sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.
sin x = 1
The value of sin is 1 for 90°.
x = 90°.
Option C is the correct answer.
Answer: 1 right angle is the maximum
Answer:
no solution
Step-by-step explanation:
| −2n | + 10 = −50
Subtract 10 from both sides.
| −2n | = −60
Since an absolute value can never equal a negative number, there is no solution.
Answer: no solution
Answer: -7
Step-by-step explanation: