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MatroZZZ [7]
3 years ago
11

Please help...

Mathematics
2 answers:
svp [43]3 years ago
5 0
8 so since it’s a square you square 8 together = 64
Dmitrij [34]3 years ago
3 0
Hey there!

First solve 2 x 4 . . .

2 x 4 = 8
This means each side of the shape is 8 inches.

To find area, multiply the two sides . . .

8 x 8 = 64 <---------

The area of the shape is 64 inches.

Hope this helps you.
Have a great day!
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What is the scale factor in the dilation if the coordinates of A prime are (–7, 6) and the coordinates of C prime are (–4, 3)?
olchik [2.2K]

Option A: \frac{1}{3} is the dilation factor

Explanation:

The Coordinates of the square ABCD are A(-21,18), B(-12,18), C(-12,9), D(-21,9)

Also, the coordinates of the square A'B'C'D' are A'(–7, 6), B'(-4,6), C'(-4,3), D'(-8,3)

Now, we shall determine the scale factor in the dilation if the coordinates A' and C'.

Since, the dilation is the enlargement of the image in the same shape but different size.

To determine the scale factor, let us divide A'C' by AC

Thus, we have,

\begin{aligned}A^{\prime} C^{\prime} &=\sqrt{(-4+7)^{2}+(3-6)^{2}} \\&=\sqrt{3^{2}+(-3)^{2}} \\&=\sqrt{9+9} \\&=\sqrt{18}\\&=3\sqrt{2} \end{aligned}

Also,

\begin{aligned}A C &=\sqrt{(-12+21)^{2}+(9-18)^{2}} \\&=\sqrt{9^{2}+(-9)^{2}} \\&=\sqrt{81+81} \\&=\sqrt{162}\\&=9\sqrt{2} \end{aligned}

Dividing A'C' by AC, we have,

\frac{A'C'}{AC} =\frac{3\sqrt{2} }{9\sqrt{2}} =\frac{1}{3}

Thus, \frac{1}{3} is the dilation factor

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3 years ago
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3 years ago
a car is traveling at a stead rate of speed. the points (1,40) and (3,y) appear on a graph of the cars distance over time. what
maria [59]

Answer:

Do you have a graph?

Step-by-step explanation:

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3 years ago
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I need help on number 2
Nina [5.8K]

9514 1404 393

Answer:

  a. 405

  b. -2

  c. 5

  d. 43

Step-by-step explanation:

I don't like doing arithmetic any more than you do, so I let a calculator do it for me. A spreadsheet works well for this, too. The function values are shown in the attachment.

Put the function argument where the variable is and do the arithmetic.

  a. h(4) = 5·3^4 = 405

  b. d(2) = 7 -9(2 -1) = -2

  c. h(0) = 5·3^0 = 5

  d. d(-3) = 7 -9(-3 -1) = 43

7 0
3 years ago
If the roots of a quadratic equation are 1±√5, then the product of the roots is
Drupady [299]
The plus-minus sign represents that there are two possible outcomes.

In this case, we have 1 \pm \sqrt{5}. When we branch out the possibilities we got 2 values: 1 + \sqrt{5} and 1 - \sqrt{5}

Those are the roots of this equation. When they ask their product, they want you to multiply both numbers.

When we multiply them: (1 + \sqrt{5}) \times( 1 - \sqrt{5})

When we FOIL the we get: 1 \times 1 - 1 \times \sqrt{5} + 1 \times \sqrt{5} - \sqrt{5} \times \sqrt{5}

Simplify:
1 - \sqrt{5} + \sqrt{5} - 5
1 - 5 = 6

So the product of the two roots of this equation is 6.
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3 years ago
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