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Alik [6]
3 years ago
15

What is 269.50 divided by 24.50

Mathematics
1 answer:
OleMash [197]3 years ago
4 0
The answer is 11

Hope this helps!!
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The last question is not 3.6
I am Lyosha [343]

I’m assuming that you only need the answer to the last one but let me know if I’m wrong :)))

I believe C would be 23.6

8 0
3 years ago
How many solutions does this equation have 3x-2x+4=2+x+2
ch4aika [34]
If you simply it down you get
x + 4 = x + 4
so X can technically be any number
8 0
3 years ago
Two students solved the same multi-step equation. Which student is correct? Explain the error. Student A Student B 2x - 4(3x + 6
Gnom [1K]

Answer:

Student B is correct

Student A failed to distribute -4 and -6 when opening the brackets in the first step

Step-by-step explanation:

The solution Student A gave was:

2x - 4(3x + 6) = -6(2x + 1) - 4

2x - 12x + 6 = -12x + 1 - 4

-10x + 6 = -12x - 3

2x = -9

x = -4 _1 2 ( -4 1/2)

The solution Student B gave was:

2x - 4(3x + 6) = -6(2x + 1) - 4

2x - 12x - 24 = -12x - 6 - 4

-10x - 24 = -12x - 10

2x = 14

x = 7

Student B is correct.

Explanation of the error:

Student A failed to distribute -4 and -6 when opening the brackets in the first step.

That is,

2x - 4(3x + 6) = -6(2x + 1) - 4

To open this bracket, we will distribute, -4 and -6 so that we get

2x (-4 × 3x) + (-4 × +6) = (-6×2x) + (-6 × +1) - 4

Then we will get

2x -12x -24 = -12x -6 -4

Adding the like terms

-10x - 24 = -12x - 10

Collecting like terms

-10x + 12x = -10 + 24

∴ 2x = 14

x = 14 / 2

Hence,

x = 7

8 0
3 years ago
Which inequality corresponds<br>to the following graph?​
alexira [117]
The first one x is greater than and equal to 34
4 0
3 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
2 years ago
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