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joja [24]
3 years ago
15

The grocery store is having a sale. For every 3 sticks of butter purchased, customers receive 1 free wedge of cheese. If the Cra

zy 80s Baby Jr. Buys 12 sticks of butter, how many free wedges of cheese will she receive?
Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

4 free wedges of cheese

Step-by-step explanation:

From the above question:

3 sticks of butter purchased = 1 free wedge of cheese

12 sticks of butter purchased = x

Cross Multiply

3 × x = 12 × 1

x = 12/3

x = 4 free wedges of cheese

Therefore, when Baby Jr. Buys 12 sticks of butter, she will receive 4 free wedges of cheese.

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Deffense [45]

Answer:

SOLVE IT UR SELF OR GET A CALCULATOR

Step-by-step explanation:

*urinates on ur property*

ANSWER : 225, 225, 225, 225, 225

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3 years ago
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mash [69]
<h3>Answer: Choice H)  2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is \sin^2 x + \cos^2x = 1

If we were to isolate sine, then,

\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, \cos x = \sqrt{1-\sin^2x}\\\\

Cosine is also positive in this quadrant.

-------------

So,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2

Therefore,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2

is an identity as long as 0 < x < pi/2

5 0
2 years ago
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Complete parts ​(a) through ​(c) below.
Yuki888 [10]

Answer:

a)t_{crit}= 1.34

b) t_{crit}=-2.539

c) t_{crit}=\pm 2.228

Step-by-step explanation:

Part a

The significance level given is \alpha=0.1 and the degrees of freedom are given by:

df = n-1= 15

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

t_{crit}= 1.34

Part b

The significance level given is \alpha=0.01 and the degrees of freedom are given by:

df = n-1= 20-1=19

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

t_{crit}=-2.539

Part c

The significance level given is \alpha=0.05 and \alpha/2 =0.025 and the degrees of freedom are given by:

df = n-1= 11-1=10

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

t_{crit}=\pm 2.228

4 0
3 years ago
Someone help me please
Gemiola [76]

Answer:

x=2\sqrt{6}

Step-by-step explanation:

Use the Pythagorean theorem:

a^2+b^2=c^2

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\sqrt{10}^2+\sqrt{14}^2=x^2

Simplify exponents using the rule \sqrt{x}^2=x :

10+14=x^2

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\sqrt{x^2}=\sqrt{24}\\  x=\sqrt{24}

Simplify in radical form: Find a common factor of 24 that is a perfect square:

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Separate:

\sqrt{4}*\sqrt{6}

Simplify:

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Finito.

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P: quadrilaterals . I hope that helps
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