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Tasya [4]
2 years ago
14

My product is 30. The differencd of the two factors is 1. The zum of the two factors is 11. What numbers am i

Mathematics
1 answer:
timurjin [86]2 years ago
5 0
A * b = 30
a - b = 1
a + b = 11

take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6

now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5

so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.
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A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c
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Answer:

C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

l\times b\times h

where l is the length, b is the base and h is the height.

Volume of box =

s^2h = 150\\\\h = \dfrac{150}{s^2}

Area of base =

\text{side}\times \text{side} = s^2

Cost of concrete for the base = $4

Cost of base($) = 4s^2

Area of roof =

\text{side}\times \text{side} = s^2

Cost of material for the roof = $2

Cost of roof ($) = 2s^2

Area of 4 walls =

4\times (sh)\\=4sh

Cost of material for the side = $2.50

Cost of material of side($) =

2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}

is the required cost function.

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3 years ago
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