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3 years ago

Which graph represents a linear function?

Mathematics

2 answers:

irakobra [83]3 years ago

5 0

Answer:

On a coordinate plane, a line has a negative slope

Step-by-step explanation:

A linear function is a function whose graph is a straight line. For example, y = 3x - 2 represents a straight line on a coordinate plane and hence it represents a linear function.

Morgarella [4.7K]3 years ago

3 0

Answer : on a coordinate plane, a line has a negative slope. the second one

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If Tim had lunch at $50.50 and he gave 20% tip, how much did he spend?

Diano4ka-milaya [45]

Answer:

<h2> Tim spent $60.60 for his lunch.</h2>

Step-by-step explanation:

The tip is 20% of what he paid for lunch. Hence

tip = 20% of 50.50 = (20/100)*50.50 = 101/100 = $10.10

Total spent

50.50 + 10.10 = $60.60

So hence, Tim spent $60.60 for his lunch.

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2 years ago

Read 2 more answers

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$