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3 years ago

The frequency table was made using a box containing slips of paper. Each slip of paper was numbered 0, 1, 2, 3, or 4

Mathematics

1 answer:

Rom4ik [11]3 years ago

4 0

What's the question???

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15z-7=14z+12 What does Z equal

Anika [276]

Answer:

Step-by-step explanation:

15z-14z=12+7

z=19

8 0

3 years ago

Drag the coordinates to match the coordinates of each point on the left with the coordinates of its reflection across the x-axis

fredd [130]

Answer:

1. (-2,-7)

2. (3,-9)

3. (7,-2)

4.(-3,9)

Step-by-step explanation:

Since the reflection is across the x-axis, the y-coordinate will be flipped.

Example: (-7,4) would become (-7,-4)

HOWEVER, if the reflection is across the y-axis, the x coordinate will be flipped.

Example: (-7,4) would become (7,4)

6 0

3 years ago

Read 2 more answers

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0

2 years ago

How can you solve problems involving direct variation?

never [62]

Answer:

Solving a Direct Variation Problem

Write the variation equation: y = kx or k = y/x.

Substitute in for the given values and find the value of k.

Rewrite the variation equation: y = kx with the known value of k.

Substitute the remaining values and find the unknown.

Step-by-step explanation:

8 0

3 years ago

Can u help me with this full sheet of work

nadezda [96]

Sometimes it takes a while to learn them but youll get it:)
1. she
2. they
3. him
4. she
5. them
6. it
7. Nate, he
8. Juwon, him
9. the sky, it
10. Mrs. P, her
11. a great catch, it
12. the coach, his OR new players, they

6 0

3 years ago

Read 2 more answers