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devlian [24]
4 years ago
14

The sum of 38 and twice a number is 124. What is the number?

Mathematics
1 answer:
deff fn [24]4 years ago
4 0
43

2x+38 = 124
2x=86
x=43
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What is the nth derivative of sin^3x?
Marrrta [24]
2??????..... idk ._.
6 0
3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
Will mark Brainliest!! :)
Georgia [21]

Step-by-step explanation:

The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.

for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.

The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.

substituting 36 for x and 10 for y in eq 1;

3(36) + 10 = 108 + 10 = 118 total students for Green High School

substituting 36 for x and 10 for y in eq2;

4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school

6 0
2 years ago
Jay organised a large wedding and 1/3 of them chose beef 5/12 of them chose Chicken and 69 of them chose vegetarian so how many
DerKrebs [107]

Answer:

276 Guests

Step-by-step explanation:

Calculation to determine how many guest were at the wedding

Guests that choose beef =1/3

Guests that choose chicken= 5/12

Guests that choose vegetarian=69

Now let calculate the how many guest were at the wedding

Let x represent the numbers of guest that were present at the wedding

Hence,

x/3 + 5x/12 + 69 = x

9x/12 + 69 = x

12x/12 - 9x/12 = 69

3x/12 = 69

x/4 = 69

x=69*4

x = 276 guests

Therefore the numbers of guests that were at the wedding is 276

7 0
3 years ago
Read 2 more answers
If f(x) = 28+x + 7, what is the value of f(-9), to the nearest<br> hundredth (if necessary)?
GREYUIT [131]

Answer:

26

Step-by-step explanation:

Problem: f(x) = 28 + x + 7

Plug in f(-9)

New equation: f(-9) = 28 + (-9) + 7

Simplify: f(-9) = 26

<u>Answer: f(-9) = 26</u>

7 0
3 years ago
Read 2 more answers
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