Answer:
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting.
Mean = 
n = 19
Since n < 30 , so we will use t test
Substitute the values :
t calculated = -0.830
degree of freedom = n-1 = 19-1 = 18
A level of significance=α=0.025
t critical = 2.093
t calculated < t critical
So, We failed to reject null hypothesis
Decision rule -0.830< 2.093 So, We failed to reject null hypothesis
Answer:
y = -1
Step-by-step explanation:
3(2) + y = 5
6 + y = 5
-6
y = 5 -6
y = -1
<u>Answer</u>:
The required is the multiplicative rate of change.
The correct answer is the second option<u> 2.5</u>
<u>Step-by-step explanation:</u>
The given function has the form of the exponential function
The general equation of the exponential function 
Wher c is constant and r is the multiplicative rate of change.
Using the given points to get the values of c and r
By using the point (0,2) ⇒∴ 
⇒ c = 2
By using the point (1,5) ⇒∴ 
⇒ r = 5/2 = 2.5
Check the answer using the other points
If x = 2 ⇒⇒⇒ 
If x = -1 ⇒⇒⇒ y=2 * 2.5^(-1) = 0.8
<u>So, the multiplicative rate of change = 2.5</u>
Answer:
A) 1
B) 1
C) 0
Step-by-step explanation:
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes
We solve this question using the z score formula
z = (x-μ)/σ/√n, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
n = number of random samples
A) Less than 10 minutes
x < 10
z = 10 - 8.2/ 1.5 / √49
z = 8.4
P-value from Z-Table:
P(x<10) = 1
B) Between 5 and 10 minutes
For x = 5 minutes
z = 5 - 8.2/ 1.5 / √49
z = -14.93333
P-value from Z-Table:
P(x = 5) = 0
For x = 10 minutes
z = 10 - 8.2/ 1.5 / √49
z = 8.4
P-value from Z-Table:
P(x = 10) = 1
The probability that the average time waiting in line for these customers is between 5 and 10 minutes
P(x = 10) - P(x = 5)
= 1 - 0
= 1
C) Less than 6 minutes
x < 6
z = 6 - 8.2/ 1.5 / √49
z = -10.26667
P-value from Z-Table:
P(x<6) = 0
