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zzz [600]
3 years ago
10

Sue's teahcer asked her to finnd 42.6 divided by 10 to the power of 2. How should Sue move the decimal point to get the correct

qoutient?
Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0
By every digits that are zero divided, you move the decimal to the left. So if it's 10, there's only one zero. So you move it one time to the left.
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The dinosaur's tail bones are at the solution point to the system of equations below.
beks73 [17]

Answer:

x = 41

y = 24

Step-by-step explanation:

Systems of equations is,

-2x - 7y = -250 ------(1)

4x - y = 140 ------(2)

Equation (1) multiplied by 2 then added to equation (2)

 -4x -14y = -500

(+)   4x - y = 140  

         -15y = -360

            y =

           y = 24

by putting y = 24 in equation (2),

4x - 24 = 140

4x = 140 + 24

x =

x = 41

For x = 41 and y = 24 both the equations are true.

Equation (1),   -2(41) - 7(24) = -250  [True]

Equation (2),   4(41) - (24) = 140  [True]

Step-by-step explanation:

6 0
3 years ago
Help asap !! will get branliest.​
umka21 [38]

Answer:

Choice A. x = y

Step-by-step explanation:

x and y are alternate interior angles.

Theorem:

If parallel lines are cut by a transversal, then alternate interior angles are congruent.

Answer: Choice A. x = y

3 0
4 years ago
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Find the area of the image below
Usimov [2.4K]
41 because if you separate the parts the square and the triangle then you would have a square that is 16 sq in diameter and a triangle that is 25sq in diameter
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4 0
3 years ago
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What is the decimal form of -4 7/8
svetlana [45]
-4\frac{7}{8}=-4\frac{7\cdot125}{8\cdot125}=-4\frac{875}{1000}=\boxed{-4.875}
4 0
3 years ago
Use matrix inversion to solve the collection of systems of linear equations. HINT [See Example 4.] (a) −x − 4y + 2z = −10 x + 2y
omeli [17]

Answer:

Step-by-step explanation:

given is a system of linear equations in 3 variables as

-x - 4y + 2z = −10\\ x + 2y - z = 11 \\x + y - z = 14

This can be represented in matrix form as

AX=B Or

\left[\begin{array}{ccc}-1&-4&2\\1&2&-1\\1&1&-1\end{array}\right] *\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-10\\11\\14\end{array}\right]

So solution set

X would be A^{-1} B

|A|=-1(-1)+4(0)+2(-1)=--1

Cofactors of A are

-1    0    -1

-2   -1     -3

0     1      2

So inverse of A is

1    2   0

0   1     -1  

1     3      -2

Solution set would be

x=12

y=-3

z=-5

8 0
3 years ago
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