What is the solution for this inequality? -10x

BaLLatris [955]

a) The polynomial in expanded form is $f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ .

b) The slant asymptote is represented by the linear function is $y = -x + 1$ .

c) There is a discontinuity at $x = 2$ with a slant asymptote.

a) In this question we are going to use the Factor Theorem, which establishes that polynomial are the result of products of binomials of the form $x-r_{i}$ , where $r_{i}$ is the i-th root of the polynomial and the grade is equal to the quantity of roots. Therefore, the polynomial $f(x)$ has the following form:

$f(x) = (x-6)\cdot (x+1)\cdot (x+3)$

And the expanded form is obtained by some algebraic handling:

$f(x) = (x-6)\cdot (x^{2}+4\cdot x +3)$

$f(x) = x\cdot (x^{2}+4\cdot x + 3)-6\cdot (x^{2}+4\cdot x +3)$

$f(x) = x^{3}+4\cdot x^{2}+3\cdot x -6\cdot x^{2}-24\cdot x -18$

$f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ (1)

The polynomial in expanded form is $f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ .

b) In this question we divide the polynomial found in a) (in factor form) by the polynomial $x^{2}-x -2$ (also in factor form). That is:

$g(x) = \frac{(x-6)\cdot (x+1)\cdot (x+3)}{(x-2)\cdot (x+1)}$

$g(x) = \frac{(x-6)\cdot (x+3)}{x-2}$ (2)

The slant asymptote is defined by linear function, whose slope ( $m$ ) and intercept ( $b$ ) are determined by the following expressions:

$m = \lim_{x \to \pm \infty} \frac{g(x)}{x}$ (3)

$b = \lim_{x \to \pm \infty} [g(x)-x]$ (4)

If $g(x) = \frac{(x-6)\cdot (x+3)}{x-2}$ , then the equation of the slant asymptote is:

$m = \lim_{x \to 2} \frac{(x-6)\cdot (x+3)}{x\cdot (x-2)}$

$m = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x^{2}-2\cdot x} \right)$

$m = 1$

$b = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x-2}-x \right)$

$b = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x - 18-x^{2}+2\cdot x}{x-2}\right)$

$b = \lim_{n \to \infty} \left(\frac{-x-18}{x-2} \right)$

$b = -1$

The slant asymptote is represented by the linear function is $y = -x + 1$ .

c) The number of discontinuities in rational functions is equal to the number of binomials in the denominator, which was determined in b). Hence, we have a discontinuity at $x = 2$ with a slant asymptote.

We kindly invite to check this question on asymptotes: brainly.com/question/4084552

8 0

2 years ago

How do i solve this?

timofeeve [1]

Answer:

Measure the sides using a ruler and measure the angle using a protractor.

3 0

3 years ago

Judy is looking to buy a textbook. The book normally costs $75.82, but it is on sale for 35% below

Trava [24]

Answer:

$49.28 is the sale cost.

Step-by-step explanation:

0.35 x 75.82 = 26.537

75.82 - 26.537

= 49.283 and round

3 0

2 years ago

What is the sound level for a noise that has an intensity of 7.6 × 10-4 watts/m2?

Greeley [361]

Sound intensity: 7.6 × 10-4 watts/m2?

To solve this problem you have to understand the threshold of hearing (Level)

Io = 10^−12 W/m²

Solve the problem:
"LI = 10×log (I / Io) dB = 10×log (7.6×10^−4 / 10^−12) dB"

and the answer is 88.81dB

Quoted answers are not mine. All credits to their internet owners.

Further help/Credits to:

https://answers.yahoo.com/question/index?qid=20130217095248AALXBjj

I'm only here to help, not get into trouble.

7 0

3 years ago

Read 2 more answers

Simplify the expression by combining like terms.

podryga [215]

Answer:

The answer: is 118

I hope this help you enjoy :D

Step-by-step explanation:

3 0

3 years ago

What is the solution for this inequality? -10x < 40