Prime factorization of 2·5·2=2^2·5
There may be more than one solution, but if we take the difference between the numbers of the sequence, we get
3-1, 11-3, 43-11
=2,8,32
which are powers of 2
=2^1, 2^3,2^5
If we believe the next difference is 2^7=128, then the next in the sequence will be 43+128=171
Answer:
point V b/c the absolute value of 5 is 5 and thats the hightest
Step-by-step explanation:
please mark brainlest
Solve for y by simplifying both sides of the equation, then isolating the variable.
y = 7x/2 - 3
The answer is c hope this helps!!!
