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oee [108]
3 years ago
9

What's the slop of this line?

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0
Slope is rise over run. It goes up 1 unit for every unit it goes over, so the slope would be 1/1, or just 1. 

1. 
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Someone help me plz !!!!!
Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

\frac{40}{1000}  =  \frac{1}{x}

so, X=25

x = What we want to find

4 0
3 years ago
Can somebody help me with Find 15% of $25
Zolol [24]

Answer:

$3.75

Step-by-step explanation:

This is the answer! Just trust me!

7 0
3 years ago
Read 2 more answers
How many pounds of cashew nuts worth 75 cents a pound must be mixed with 10 pounds of pecans worth $1.50 a pound to make a mixtu
Trava [24]
Let c represent the weight of cashews and p the weight of pecans.

Then c + 10 = total weight of the nut mixture.

An equation for the value of the mixture follows:

 $1.50(10 lb) + $0.75c = (c+10)($1.00)

Solve this equation for c:  15 + .75c = c + 10.  Subtract .75c from both sides:

15 = 1c - 0.75c + 10.  Then 5=0.25c, and c = 5/0.25, or 20.

Need 20 lb of cashews.


Check:  the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15.  The total value of the cashews is (20 lb)($0.75/lb), or $15.     Does (20 lb + 10 lb)($1/lb) = $15 + $15?  Yes.  So c= 20 lb is correct.
3 0
3 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
3 years ago
What is the product?<br><br> (5r − 4)(r2 − 6r + 4)
maxonik [38]

Answer:

1r

Step-by-step explanation:

(5r-4)(2r-6r+4)

1(5r-4)+1(2r-6r+4)

5r-4+2r-6r+4

5r+2r-6=1r

1r-4+4

-4+4=0

1r

7 0
2 years ago
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