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oee [108]
3 years ago
9

What's the slop of this line?

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0
Slope is rise over run. It goes up 1 unit for every unit it goes over, so the slope would be 1/1, or just 1. 

1. 
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In the right triangle shown m
GREYUIT [131]
I needa see it tho for I could help
8 0
3 years ago
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Trigonometry help?? Thank you so much!!
liq [111]

Answer:

7) a = 60; b = 100

8) c = 20

9) d = 45

Step-by-step explanation:

7)

a + 120 = 180

a = 60

b + 80 = 180

b = 100

8)

5c + 4c = 180

9c = 180

c = 20

9)

3d + d = 180

4d = 180

d = 45

6 0
3 years ago
Find the area using the given image.
ArbitrLikvidat [17]

Answer:

4.

Step-by-step explanation:

Area = 1/2 * base + height

= 1/2 * 2 * 4

= 4 unit^2.

3 0
2 years ago
[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimens
MissTica

Answer:

  6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

  x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

  h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

  V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

  dV/dx = 0 = 27 -(3/4)x²

  x² = (4/3)(27) = 36

  x = 6

  h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

<em>Comment on maximum volume, minimum area</em>

In the general case of<em> an open-top box</em>, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a <em>closed top</em>, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

7 0
3 years ago
Points N and R both lie on circle O. Line segment RQ is tangent to the circle at point R.
4vir4ik [10]

Answer:

15.0

Step-by-step explanation:

Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.

The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)

4 0
3 years ago
Read 2 more answers
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