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andrezito [222]
2 years ago
7

A continuous random variable X has cdf F(x)=x² b (a) Determine the constants a and b. for a < 0, for 0 < x < 1, for x &

gt; 1.​

Mathematics
1 answer:
Karolina [17]2 years ago
8 0

Any proper CDF F(x) has the properties

• \displaystyle \lim_{x\to-\infty} F(x) = 0

• \displaystyle \lim_{x\to+\infty} F(x) = 1

so we have to have a = 0 and b = 1.

This follows from the definitions of PDFs and CDFs. The PDF must satisfy

\displaystyle \int_{-\infty}^\infty f(x) \, dx = 1

and so

\displaystyle \lim_{x\to-\infty} F(x) = \int_{-\infty}^{-\infty} f(t) \, dt = 0 \implies a = 0

\displaystyle \lim_{x\to+\infty} F(x) = \int_{-\infty}^\infty f(t) \, dt = 1 \implies b = 1

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m∠8 + m∠7 = 180°


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substitute:

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<span><span>The correct answers are:
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If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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