The expected count of visits is the mean or average visits to each feeder
The expected count of visits to the third feeder is 87.5
<h3>How to determine the expected count of visit?</h3>
The table of values is given as:
Feeder 1 2 3 4
Observed visits 80 90 92 88
In this case, the null hypothesis implies that the visits to each feeder are uniformly distributed
So, the expected count is calculated using:
Expected count =Visits/Feeders
This gives
Expected count = 350/4
Evaluate the quotient
Expected count = 87.50
Hence, the expected count of visits to the third feeder is 87.5
Read more about chi square goodness of fit test at:
brainly.com/question/4543358
Answer:
$51.70
Step-by-step explanation:
I don't know how to explain it actually so I am just going to do this...
y= 0.1(x + 20) +7
y=0.1x + 2 + 7
y=0.1x +9
y=0.1(427)+9
y=42.7+9
y=51.7
So, maybe the answer is $51.70.
The jet could fly 2,000 miles in 8 hours and the rate of speed is 250miles per hour.
12w - 27 = -34 + 14
w = 7/12
A -2w+21=-8w+36
w=17/8
B -5/6 w + 2 = -34+14w
w=216/89
C -47-10w=-9w-40-3w
w= 7/2
D 8/7w=13/14w+2
w=28/5
