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KengaRu [80]
3 years ago
14

The function below takes one parameter: an integer (begin). Complete the function so that it prints the numbers starting at begi

n down to 1, each on a separate line. There are two recommended approaches for this: (1) use a for loop over a range statement with a negative step value, or (2) use a while loop, printing and decrementing the value each time.
Computers and Technology
1 answer:
arlik [135]3 years ago
8 0

Answer:

Program is in C++

Explanation:

C++ Code

1) By using For Loop

void forLoopFunction(int value){

for(int start=value; start>0; start--){

 cout<<start<<endl;

}

}

Explanation

Start for loop by assigning the loop variable to parameter value and condition will be that loop variable will be greater then 0 and at the end decrements the loop variable.

2) By usin WhileLoop

void whileLoopFunction(int value){

 while(value>0){

 cout<<value<<endl;

 value--;

 }

}

Explanation

In while loop first add the condition as variable must be greater then 0 and then print the value with endl sign to send the cursor to next line and at the end of the loop decrements the variable.

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A hotel salesperson enters sales in a text file. Each line contains the following, separated by semicolons: the name of the clie
timama [110]

Answer:

see explaination

Explanation:

Java code

//Header file section

import java.util.Scanner;

import java.io.*;

//main class

public class SalesTestDemo

{

//main method

public static void main(String[] args) throws IOException

{

String inFile;

String line;

double total = 0;

Scanner scn = new Scanner(System.in);

//Read input file name

System.out.print("Enter input file Name: ");

inFile = scn.nextLine();

FileReader fr = new FileReader(new File(inFile));

BufferedReader br = new BufferedReader(fr);

System.out.println("Name \t\tService_Sold \tAmount \tEvent Date");

System.out.println("=====================================================");

line = br.readLine();

//Each line contains the following, separated by semicolons:

//The name of the client, the service sold

//(such as Dinner, Conference, Lodging, and so on)

while(line != null)

{

String temp[] = line.split(";");

for(int i = 0; i < temp.length; i++)

{

System.out.print(temp[i]+"\t");

if(i == 1)

System.out.print("\t");

}

//Calculate total amount for each service category

total += Double.parseDouble(temp[2]);

System.out.println();

line = br.readLine();

}

//Display total amount

System.out.println("\nTotal amount for each service category: "+total);

}

}

inputSale.txt:

Peter;Dinner;1500;30/03/2016

Bill;Conference;100.00;29/03/2016

Scott;Lodging;1200;29/03/2016

Output:

Enter input file Name: inputSale.txt

Name Service_Sold Amount Event Date

=====================================================

Peter Dinner 1500 30/03/2016

Bill Conference 100.00 29/03/2016

Scott Lodging 1200 29/03/2016

Total amount for each service category: 2800.0

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Prison or juvenile detention of course, its a violation

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A menu bar organizes related commands together, under a tab.
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4 years ago
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Answer:

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BRAINLIEST ANSWER AWARDED PLEASE HELP
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When a formula produces output that is too lengthy to fit in the spreadsheet cell, the error that will show is "#####". When you enter an invalid cell reference in a formula, for instance using "AVE(" instead of "AVERAGE("; the error that will show is "#NAME?". When you type text in cells that accept numeric data, for instance adding 1 + 1 + A; then the error that will show is "#VALUE". Lastly, when you type in a cell reference that does not exist, the error that will show is "#REF".
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