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KengaRu [80]
3 years ago
14

The function below takes one parameter: an integer (begin). Complete the function so that it prints the numbers starting at begi

n down to 1, each on a separate line. There are two recommended approaches for this: (1) use a for loop over a range statement with a negative step value, or (2) use a while loop, printing and decrementing the value each time.
Computers and Technology
1 answer:
arlik [135]3 years ago
8 0

Answer:

Program is in C++

Explanation:

C++ Code

1) By using For Loop

void forLoopFunction(int value){

for(int start=value; start>0; start--){

 cout<<start<<endl;

}

}

Explanation

Start for loop by assigning the loop variable to parameter value and condition will be that loop variable will be greater then 0 and at the end decrements the loop variable.

2) By usin WhileLoop

void whileLoopFunction(int value){

 while(value>0){

 cout<<value<<endl;

 value--;

 }

}

Explanation

In while loop first add the condition as variable must be greater then 0 and then print the value with endl sign to send the cursor to next line and at the end of the loop decrements the variable.

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Which of the following statements concerning a short in a series circuit is true?
Romashka [77]

Answer:

what is the answers it gave you?

6 0
3 years ago
The development team recently moved a new application into production for the accounting department. After this occurred, the Ch
Gnesinka [82]

Answer:

B

Explanation:

User Acceptance Testing (UAT) is the testing done by end users who is going to use that application. In these testing they will test  whether the application meets all the functional requirements of the end user. If it passed then only the application will move to the production. This will ensure that the application meets the user requirements before it put into the usage.

The Answer is B

5 0
3 years ago
Write a program that prompts the user to enter in a postive number. Only accept positive numbers - if the user supplies a negati
marusya05 [52]

Answer:

The c++ program to check prime numbers is shown below.

#include <iostream>

using namespace std;

int main() {

   int num, prime=0;

   do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

   

   if(num==1 || num==2 || num==3)

       cout<<num<<" is a prime number."<<endl;

   else if(num%2 == 0)

       cout<<num<<" is not a prime number."<<endl;

   else

   {

       for(int k=3; k<num/2; k++)

       {

           if(num%k == 0)

               prime++;

       }    

   if(prime>1)

       cout<<num<<" is not a prime number."<<endl;

   else

       cout<<num<<" is a prime number."<<endl;

   }

}

OUTPUT

Enter a positive number.

-7

Invalid number. Enter a positive number

0

Enter a positive number.

79

79 is a prime number.

Explanation:

The user input is validated for positivity. A do while loop along with an if statement is implemented for verification.

do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

The test for prime number is done by using multiple if else statements.

If user inputs 1, 2, or 3, message is displayed.

Else If user inputs an even number, message is displayed for not prime. This is done by taking modulo of the number upon division by 2.

Else if user inputs neither an even number nor a number less than 3, the modulus of the number is taken with divisors beginning from 3 up to half of the input number.

For this, an integer variable prime is initialized to 0. A number can be completely divisible by itself or by its factors.

If the number is divisible by any of the divisors, value of variable prime is increased by 1. If value of prime is greater than 1, this means that the user input is divisible by more than one divisor. Hence, the given number is not a prime number.

5 0
3 years ago
Wikis are designed for ________, which is allowing people to contribute more than just posting a response
Viefleur [7K]

Answer:

collabirations

Explanation

Wikis are designed for collabirations, which is allowing people to contribute more than just posting a response.

4 0
3 years ago
You are running an 802.11g wireless router in mixed mode. You have three 802.11g wireless NICs connected to the router. A new us
notka56 [123]

Complete Question:

You are running an 802.11g wireless router in mixed mode. You have three 802.11g wireless NICs using the router. A new user connects using an 802.11b wireless NIC. What will happen?

Group of answer choices.

A. The user with 802.11b will access the network at 11Mbps while the users with 802.11g will access the network at 54 Mbps.

B. The user with 802.11b will not be able to communicate on the network.

C. The user with 802.11b will access the network at 11 Mbps. The users with 802.11g will access the network at 54 Mbps unless they are communicating with the 802.11b device,which will be at 11 Mbps.

D. All users will access the network at 11 Mbps.

Answer:

D. All users will access the network at 11 Mbps.

Explanation:

A 802.11g is one of the wireless network standards developed by the Institute of Electrical and Electronics Engineers (IEEE) which operates on a 2.4 GHz microwave bandwidth and as a result can only transmit over a short distance. The 802.11g has a data transfer rate or throughput of 54 megabits per seconds (Mbps).

Basically, the 802.11b is a similar standard to the 802.11g wireless standard that typically allows the transmission (transfer) of data for up to 11 megabits per seconds (Mbps).

In this scenario, you are running an 802.11g wireless router in mixed mode. You have three 802.11g wireless NICs using the router. A new user connects using an 802.11b wireless NIC.

Hence, what will happen is that, all the users will access the network at 11 Mbps.

6 0
3 years ago
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