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3 years ago

Hey can you please help me posted picture of question

Mathematics

2 answers:

larisa [96]3 years ago

5 0

$(5x - 2)^2 = 15$

Square root both sides:
$5x - 2 = \pm\sqrt{15}$

Add 2 to both sides:
$5x = pm\sqrt{15} + 2$

Divide both sides by 5:
$x = \dfrac{ \pm\sqrt{15} + 2}{5}$

Answers:
$x = \dfrac{ \sqrt{15} + 2}{5} \ or \ \dfrac{ - \sqrt{15} + 2}{5}$

Answer: (B) and (E)

Leto [7]3 years ago

4 0

Ans: Option (B) and Option (E)

Explanation:

Given equation:
(5x-2)^2 = 15

Take square-root on both sides:
$\sqrt{(5x-2)^2} = \sqrt{15} \\ 5x - 2 = \pm \sqrt{15} \\ x = \frac{ \pm \sqrt{15} + 2}{5}$

Also plus-minus are involved, hence Options (B) and (E) are both correct.

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Explaining a Rule for Dividing Fractions

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Answer:

One rule for dividing fractions is the rule where instead of doing 13/43, you can do 13 times 1/43.

Step-by-step explanation:

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3 years ago

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In one U.S city, the taxi cost is $2 plus $0.60 per mile. If you are traveling from the airport, there is an additional charge o

anzhelika [568]

Answer:

60 miles

Step-by-step explanation:

Let

x ----> the number of miles

we know that

The number of miles multiplied by $0.60 per mile plus $2 plus the charge of $5.50 for tolls (because you are travelling from the airport) must be equal to $43.50

The linear equation that represent this problem is

$0.60x+2+5.50=43.50$

Solve for x

Combine like terms left side

$0.60x+7.50=43.50$

subtract 7.50 both sides

$0.60x=43.50-7.50$

$0.60x=36$

divide by 0.60 both sides

$x=60\ miles$

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3 years ago

What is the volume of this rectangular prism?<br> 3/2cm<br> 1/2<br> 4 cm

Reptile [31]

Answer:

7.62

Step-by-step explanation:

length* width* height = 3/2*1/2*4=7.62 cm

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1 year ago

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2 years ago

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A candy store has ten giant pieces of candy! Find the probability of each event. There are 4 gumdrops, 3 lolipops, 2 jellybeans,

AveGali [126]

Answer:

1. P = 9/90 = 1/10

2. P = 16/90 = 8/45

3. P = 10/90 = 1/9

4. P = 4/90 = 2/45

Step-by-step explanation:

Total no. of candy = 10

No. of Gumdrops = 4

No. of Lollipops = 3

No. of Jellybeans = 2

No. of Peppermint = 1

1. To find the probability that the child will pick a peppermint or jellybean, we will add the probabilities of both the candies.

P(Peppermint) = No. of Peppermint/Total no. of candy

= 1/10

P(Jellybean) = No. of Jellybean/Total no. of candy

= 2/10

P(Peppermint or Jellybean) = 1/10 + 2/10

P(Peppermint or Jellybean) = 3/10

Then, the child picks a lollipop. Note that after picking a peppermint or a jellybean, the number of candies left are 9. So,

P(Lollipop) = No. of Lollipops/Total no. of candy

P(Lollipop) = 3/9

To compute the probability that the child will pick a peppermint or a jellybean and then a lollipop,

P = P(Peppermint or Jellybean) x P(Lollipop)

= 3/10 x 3/9

P = 9/90 = 1/10

2. Probability that a child will pick a lollipop or peppermint:

P(Lollipop or Peppermint) = P(lollipop) + P(peppermint)

= 3/10 + 1/10

P(Lollipop or Peppermint) = 4/10

Then the child picks a gumdrop. Note that the number of candies remaining are 9. So,

P(Gumdrop) = 4/9

The probability that the child picks a lollipop or peppermint and then a gumdrop:

P = P(Lollipop or Peppermint) x P(Gumdrop)

= 4/10 x 4/9

P = 16/90 = 8/45

3. Probability that a child will pick a jellybean:

P(Jellybean) = No. of Jellybeans/Total no. of candy

P(Jellybean) = 2/10

Then the child picks a peppermint or a gumdrop. Note that one candy has been picked out so there are 9 candies left in total.

P(Peppermint or Gumdrop) = P(peppermint) + P(Gumdrop)

= 1/9 + 4/9

P(Peppermint or Gumdrop) = 5/9

The probability that a child picks a jellybean then a peppermint or a gumdrop is:

P = P(Jellybean) x P(Peppermint or Gumdrop)

= 2/10 x 5/9

P = 10/90 = 1/9

4. P(peppermint) = 1/10

Then the child picks a gumdrop. (remaining candies are 9)

P(Gumdrop) = 4/9

Probability that a child will pick a peppermint then a gumdrop:

P = P(peppermint) x P(gumdrop)

= 1/10 x 4/9

P = 4/90 = 2/45

5 0

3 years ago