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-Dominant- [34]

2 years ago

6

The following sequence of operations is done on a number. Multiply by 5, add 2, subtract 10, multiply by 2. The final result is

44. What is the original number? Plz help I will give you 100 points

1 answer:

strojnjashka [21]2 years ago

4 0

answer the original number is 6

(5x + 2 - 10) *2 = 44

10x + -16 = 44

10x = 60

x=6

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Please can you give the answer of this, 8x+5y=23 -8x+9y=-19

Lady_Fox [76]

8X+5Y=23
8X=23-5Y

-8X+9Y= -19 multiple all by -1
8X-9Y=19
8x=23-5y
Plug that in
23-5Y-9Y=19
-14Y=19-23
-14Y= -4
Y=1

8X=23-5Y
8X=23-5•1
8X=23-5
8X=18
X=18/8
X=9/4

3 0

2 years ago

The total profit from the Spanish club fund-raiser varies directly with the number of dinner tickets sold. If the sale of 22 tic

worty [1.4K]

Answer:

61 tickets

Step-by-step explanation:

It is given that,

The total profit from the Spanish club fund-raiser varies directly with the number of dinner tickets sold.

If the sale of 22 tickets results in a profit of $253.

Profit in 1 ticket = $\dfrac{253}{22}=\$11.5$

Let x tickets are sold in order to reach the fund-raising goal of $700.

$x=\dfrac{22}{253}\cdot700\\\\=\$60.86$

or

= 61 tickets

Hence, 61 tickets must be sold to reach the fund-raising goal of $700.

6 0

2 years ago

if 4/5 cups of brown sugar is needed for every 3/4 cup flour how much is needed for 1 pound of flour.

attashe74 [19]

1/2of a pound I hope that helps

4 0

2 years ago

Read 2 more answers

2(3) squared answer and steps.

olga55 [171]

Step-by-step explanation:

2(3)

2×3=6

6×6=36

36 is the correct answer i hope it helps you

4 0

2 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So $n = 5, s = \frac{107}{\sqrt{5}} = 47.86$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 526}{47.86}$

$Z = -2.42$

$Z = -2.42$ has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0

2 years ago