It is just 5.0 and you move the decimal right six places
<span>lim (x → π/2) (sinx)^(tanx)
= lim (x → π/2) e^[(tanx) ln (sinx)]
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1)
lim (x → π/2) (tanx) ln (sinx)
= lim (x → π/2) [ln(sinx) / cotx]
Using L'Hospital'stheorem,
= lim (x → π/2) [- cotx / cosec^2 x]
= 0
Plugging in ( 1 ),
required limit = e^0 = 1
=>Answer is 1.
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Answer:
197in^2
Step-by-step explanation:
5x5=25(top face)
5x5=25(left face)
9x5=45(bottom face)
6.4x5=26(right face)
Front and behind face: trapezoid area (trapezoid formula h x (a+b)/2)
(5+9)/2 x 5=7x5=35
35+35+25+25+45+25=197in^2
With this one, since the problem says it will cost $35 per hour, then that will be based on the amount of hours spent on the job, so 35 gets the x, with x equaling the number of hours it took to do the job. $78 is the cost for a part so it is going to stay at 78. So your answer will be D. 35x+78≤225.