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love history [14]
3 years ago
11

11. Why does lithium chloride dissolve in water and not gasoline?

Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer:

Lithium chloride is an ionic compound

Explanation:

In chemistry it is usually said that like dissolves like. This implies that the intermolecular forces in a solute and its solvent must be similar before effective dissolution can take place.

Lithium chloride is an ionic compound. Ionic compounds consists of ions and only dissolve in polar solvents. They dissolve in polar solvents because of the interaction of the polar solvents with the ions in an ionic compound.

Gasoline is a non polar solvent. Being a nonpolar solvent, it does not interact with the ions in lithium chloride hence gasoline cannot dissolve lithium chloride.

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Answer:

32.7 grams of Zn will remained in the crucible after cooling.

Explanation:

2ZnS+3O_2 \rightarrow 2ZnO + 2SO_2..[1]

ZnO+C\rightarrow Zn+CO..[2]

Adding [1] + 2 × [2] we get:

2ZnS+3O_2+2C \rightarrow 2Zn + 2CO+2SO_2..[3]

Moles of ZnS in crucible = 0.50 mol

According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.

Then 0.50 moles of ZnS will give:

\frac{2}{2}\times 0.50 mol=0.50 mol of Zn.

Mass of 0.50 moles of Zn =

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32.7 grams of Zn will remained in the crucible after cooling.

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4 years ago
Describe how hydrogen and oxygen form water
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You are working in a lab when radiation alarms go off. You are able to hide inside a steel cabinet, whose sides are about 1.5 in
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Answer:

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Explanation:

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Elements                        Titanium            Aluminium        Vanadium

Percentage                    64.39                 24.19                   11.42

Divide all through by their molar mass

                                     64.39 / 47.87      24.19 / 27               11.42 / 50.94

                                       =  1.345                = 0.896                 = 0.224

Divide all though  by the smallest number (0.224)

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                                     = 6                         = 4                             = 1

The Empirical Formular is given as; Ti₆Al₄V

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