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Natali5045456 [20]
3 years ago
11

Do all of em 1 to conclusion :) 20 points & brainliest

Chemistry
1 answer:
Anit [1.1K]3 years ago
4 0

Answer:

The metric system is the preferred system of scientific units for several reasons: The majority of countries in the world employ the metric system of measurement. Because metric units are decimal-based, they are easily converted by moving the decimal point.

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Answer:

4 sun , planet, moon are the components in the correct order

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3 years ago
The distance between any two successive places where the shape of the wave repeats itself
Anit [1.1K]
Wave length is the answer.
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Read 2 more answers
An unknown mass of aluminum requires 6290 joules to raise
Alex Ar [27]

Answer:

124.579 g

Explanation:

Amount of heat required to change the temperature of body is given by the equation given below

Q = m* c * ΔT ____________________equation A

where Q is the total heat energy required by the any object

c is the specific heat capacity of the body J/gK

ΔT is the difference of final temperature of the object and initial temperature of the object

______________________________________

Given Q = 6290 joules

c = 0.900 J/gK

To calculate the temperature in kelvin from Celsius

we can use the formula

K = C + 273

initial temperature  = 23.9°C

initial temperature on kelvin scale =  23.9° + 273 = 296.9

Final temperature  = 80°C

initial temperature on kelvin scale =  80° + 273 = 353

ΔT(temperature difference) = 353 - 296.9 = 56.1

___________________________________________

let the mass of of the  aluminum be m g

substituting the value of Q , c, ΔT in equation A we have

Q = m* c * ΔT

=> 6290 = m * 0.900 * 56.1

=> m = 6290/(0.900 * 56.1 )

=> m = 6290/50.49

=> m = 124.579 g

The mass of the  aluminum is 124.579 g

8 0
3 years ago
Is it iron or lead ???
san4es73 [151]
^^ they are correct
8 0
3 years ago
C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work
irakobra [83]

Answer:

\Delta H_{comb}=2043.85kJ/mol

Explanation:

Hello there!

In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:

\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}

Thus, given the values of the enthalpies of formation on the attached file, we obtain:-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol

Best regards!

5 0
3 years ago
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