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sergejj [24]
3 years ago
14

Which equations are in standard form? Check all that apply

Mathematics
1 answer:
NemiM [27]3 years ago
8 0
Standard form is y=mx+b
<span>y = 2x + 5
</span><span>y = x – 9</span>
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Which method can't you use to solve x²+7x=0.
scoray [572]

Answer:

Factoring

Step-by-step explanation:

x^2 + 7x = x(x + 7) = 0

So

x = 0 or x = -7

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If you eat too much, you will fall ill. Is that a noun adjective or adverb clause sentence?
azamat
It is an adverb clause.
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What is the area of the shaded region?​
olga_2 [115]
It’s 4pi-(2•3) =6.5663 roughly
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Taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
Novosadov [1.4K]

Answer:

Step-by-step explanation:

Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.

For a random single taxi std deviation is 2.20

But for a sample of size 10, std deviation would be

\frac{2.20}{\sqrt{10} }

This would be less than the 2.20

Because std devition is less for sample we get a big z score for the sample than the single.  

As positive values of z increase we find that probability would decrease since normal curve is bell shaped.

So single taxi fare would have higher probability than sample.

B) Here >24.

By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10

3 0
3 years ago
AMERICAN AIRLINES HAS A POLICY OF BOOKING AS MANY AS 15 PEOPLE ON AN AIRPLANE THAT CAN SEAT ONLY 14. (PAST STUDIES HAVE REVEALED
Blizzard [7]

Using the binomial distribution, there is a 0.0874 = 8.74% probability that not enough seats will be available.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are given by:

n = 15, p = 0.85.

The probability that not enough seats will be available is P(X = 15), as the only outcome in which not enough seats will be available is when all 15 people who bought the ticket show up, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 15) = C_{15,15}.(0.85)^{15}.(0.15)^{0} = 0.0874

0.0874 = 8.74% probability that not enough seats will be available.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

8 0
1 year ago
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