ABC is an isosceles triangle so AB = BC
Plug in
x + 4 = 3x - 8
-2x = - 12
x = 6
AC = x = 6
Answer
6 units
Answer:
A C and D
Step-by-step explanation:
The law of sine is the nothing but the relationship between the sides of the triangle to the angle of the triangle (oblique triangle).
The value of the
is 3.2 (rounded to the nearest tenth). The option 2 is the correct option.
<h3>
What is law of sine?</h3>
The law of sine is the nothing but the relationship between the sides of the triangle to the angle of the triangle (oblique triangle).
It can be given as,

Here
are the angle of the triangle and
are the sides of that triangle.
Given information-
The triangle for the given problem is attached below.
In the triangle the base of the triangle is 2.6 units long.
The sine law for the given triangle can be written as,

As the value of
side is known and the value of
has to be find. Thus use

Put the values,

Solve it for the
,

Hence the value of the
is 3.2 (rounded to the nearest tenth). The option 2 is the correct option.
Learn more about the sine law here;
brainly.com/question/2264443
Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
Answer:
<h3>
HJ = 15</h3>
Step-by-step explanation:
To get the length of segment HJ if H lies at (-1,7) and J lies at (8,-5), we will use the formula for calculating the distance between two points as shown;
D = √(x₂-x₁)²+(y₂-y₁)²
From the coordinates x₁ = -1, y₁ = 7, x₂ = 8, y₂ = -5
HJ = √(8-(-1))²+(-5-7)²
HJ = √(8+1)²+(-12)²
HJ = √81+144
HJ = √225
HJ = 15
<em>Hence the length of segment HJ is 15 units</em>