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nexus9112 [7]
3 years ago
11

Simplify. -6u? +10u?

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0

Answer:

4u

Step-by-step explanation:

-6 + 10 = 4

Now just add the u!

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The lengths of the sides of a triangle are in the ratio
Anton [14]
HOW TO SOLVE:

1) use x as a variable
2) the starting equation is:
          4x + 3x + 5x = 18

3) add all the like terms on the left side of the equation:
          12x = 18

4) Divide by 12 on both sides:
          x=1.5

5) Find the lengths of the sides:

        - 4x = 4(1.5) = 6

        - 3x = 3(1.5) =  4.5

       - 5x = 5(1.5) = 7.5

SO, the lengths of the sides of this triangle are: 6, 4.5, and 7.5
5 0
3 years ago
Nina can type 124 words in 4 minutes.at this rate how many words can nina type in an hour
Ludmilka [50]

Answer:

<em>1,860</em>

Step-by-step explanation:

FIRST:

we divide 124 by 4 because in 4 minutes he can type 124 words, and we need to figure out how many he can type in a minute.

124 divided by 4 is 31. (they can type 31 wpm)

NEXT: now we know they can type 31 wpm, we need to multiply that number by 60 because there are 60 minutes in an hour.

31 x 60 = 1,860

therefore, they can type 1860 words per hour

hope i helped have a great day/night! :'')

6 0
3 years ago
The back of a dog house is composed of a square and a triangle . How much wood wood is needed for the back of the dog house to t
Anastaziya [24]

Answer:

68

Step-by-step explanation:

I just know I was in class with my teacher

8 0
3 years ago
A. Seven fewer than t
Katyanochek1 [597]

7 fewer than t is:

t - 7

I hope this helps

7 0
3 years ago
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

Now, the probability of both black and red card = $ \frac{1}{2} \times \frac{26}{51} $

$ = \frac{\textbf{13}}{\textbf{51}} $

Hence, the answer.

5 0
3 years ago
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