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Marizza181 [45]
3 years ago
8

CAN SOMEONE LLEASE HELP ME IM SO LOST!!

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer: 1324 in^2

Step-by-step explanation:

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If the third term in a geometric sequence is 20, and the fifth term in the sequence is 5, what is the ratio (multiplier)?
Talja [164]
Term:    3     4      5
 Value  20    ..      5
            20  20r  20r^2
So 20r^2 = 5
         r^2 = 1/4
           r  =  1/2
5 0
3 years ago
Brielle and Joshua are running a half marathon race, which is 13.1 miles long. It
Hitman42 [59]

Answer:Brielle will run the half marathon race faster.Brielle will take 1 hour 44 minutes and 48 seconds, Joshua will take 2 hours 37 minutes and 12 seconds

Step-by-step explanation:

10 / 1.25 = 8

8 minutes a mile

18 / 1.5 = 12

12 minutes a mile

Brielle will run the half marathon race faster.

8 x 13.1 =104.8

12 x 13.1=157.2

104.8 - 60=

44.8

60 seconds x .8= 48

Brielle will take 1 hour 44 minutes and 48 seconds

157.2 - 120 = 37.2

60 seconds x .2 = 12

Joshua will take 2 hours 37 minutes and 12 seconds

8 0
3 years ago
What is the measure of the missing angle​
Allisa [31]

Answer:

33

Step-by-step explanation:

What you do is you take 57 and since it is a right triangle you take 90 and add them together. You will get 147. You will then minus this from 180 to get 33.

3 0
3 years ago
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Solve this pleaseeeee
Ivan

Answer:

-4 < n ≤ 5

Step-by-step explanation:

________________

7 0
2 years ago
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
1 year ago
Read 2 more answers
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