Question

What is the x-intercept of the graph of the function f(x)=x2-16x+64?

Answer 1

Answer:

x-intercept: (8,0)

Step-by-step explanation:

Given: $f(x)=x^2-16x+64$

For x-intercept, Put y=0 and solve for x.

x-intercept: It is a point where y-coordinate zero.

$x^2-16x+64=0$

$x^2-8x-8x+64=0$

$(x-8)(x-8)=0$

Equate each factor to 0 and solve for x

x-8 = 0    , x-8 = 0

x=8,8

x-intercept: (8,0)

Hence, The x-intercept is 8.

Answer 2

X=8 

Explanation: 
f(x)=x^2-16x+64+(x-8)^2

You see there is a double x- intercept by the 8. So the parabola is tangent to the x axis. So x=8 f(x)=0 

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