Answer:
Step-by-step explanation:
hello :
x²+6x+9 = 20
(x+3)²-20 = 0
(x+3)²-√20 = 0
(x+3-√20)(x+3+√20)=0
x+3-√20=0 or x+3+√20=0
x = -3+√20 or x = -3-√20 answer B
Answer:
Step-by-step explanation:
Because you are multiplying you add the exponents together. -5+6=1 so you only have 3 to the power of one left over or just 3 in the parentheses. Then multiply 2x3 to get 6.
Answer:
Step-by-step explanation:
Synthetic division is one way to determine whether or not a given number is a root of the quadratic. x^2 − 12x − 20 can be rewritten as x^2 - 12x + 36 - 36 - 20, or (x - 6)^2 - 56, which does not have integer solutions:
(x - 6)^2 - 56 = 0 becomes (x - 6)^2 = 56, which works out to x - 6 = ± 2√14.
None of the possible roots suggested in this problem turns out to be an actual root.
correct response: PRIME