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3 years ago

Is my answer correct? if not please tell me the correct answer.

Mathematics

2 answers:

ASHA 777 [7]3 years ago

8 0

m = 6/5 is the slope intercept

y = mx + b to find the slope of m

n200080 [17]3 years ago

5 0

Slope intercept is y=mx + b

So, you would need to add 6x to both sides giving you,

5y = 6x - 10

Now you would divide both sides by 5 giving you,

y= $\frac{6}{5}$ x - 2

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Need help Choices 4 3 2 1

-Dominant- [34]

Answer:

Step-by-step explanation:

The amplitude is the maximum distance away from the middle of the wave. Here we can see that the middle of the wave is the x axis and the farthest point (largest difference between the y coordinate of the x-axis, or the line y = 0, and the wave) is 1 unit away.

4 0

3 years ago

Read 2 more answers

Please Help! B belongs to AC D belongs to lineAF

Anvisha [2.4K]

Answer:

x = 27

Step-by-step explanation:

∠ CAD and ∠ EDF are corresponding angles and are congruent, so

∠ CAD = 2x

The sum of the 3 angles in Δ ABD = 180°

sum the angles and equate to 180

72 + 2x + 2x = 180

72 + 4x = 180 ( subtract 72 from both sides )

4x = 108 ( divide both sides by 4 )

x = 27

5 0

3 years ago

6. GODEEPER Anders makes 7 fruit cups. He puts 2 green

Pie

Answer:

Step-by-step explanation:

because 2+2+2=6×7=42

5 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Another set of help? i need a hand lol

Zepler [3.9K]

Answer: C=14π≈43.98 ft

Step-by-step explanation:

To find the circumference of the circle, we use the equation C=2πr or C=πd. These 2 equations are equivalent because 2r is the same as d, diameter. In this case, we can use C=πd because the problems already gives us the diameter.

C=πd

C=14π≈43.98 ft

I hope this helps!

5 0

3 years ago