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3 years ago

Does anyone know the answer to this? I tried my best

Mathematics

1 answer:

Anna11 [10]3 years ago

8 0

A. Corresponding angles bc 1 and 5 are on the same side and they aren’t on the inside or the outside and if u scuot I’m down then they will be the same

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A circle has center

Fed [463]

Note that the equation of the circle is

(x-h)² +(y-k)² =r²

where centre is (h,k)

the equation of the circle based on the information given

(x-3)² +(y-4)² =r²
and the point on the circle (3,-2)

substitute into the equation

(3-3)² +(-2-4)² =r²

r=6 or r=-6

since r is radius, we reject r=-6 since radius must be nonnegative.

the radius is 6

5 0

1 year ago

Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

MrRa [10]

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

Answer:

67.5 $mm^3$

Step-by-step explanation:

Given that :

Cylinder A and cylinder B are similar.

Let volume of cylinder A = 20 $mm^3$

We know the volume of a cylinder is given by V = $\pi r^2 h$

where, r is the radius of the cylinder

h is the height of the cylinder

We have to find the scale factor.

The length scale factor is = $\frac{6}{4}$

$=\frac{3}{2}$

Area scale factor $=\left(\frac{3}{2}\right)^2$

$=\frac{9}{4}$

∴ Volume scale factor $=\left(\frac{3}{2}\right)^3$

$=\frac{27}{8}$

Therefore, the volume of cylinder B is $=20 \times \frac{27}{8}$

= 67.5 $mm^3$

5 0

3 years ago

Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

3 0

3 years ago

A recipe for 10 servings of raspberry sorbet calls for 2 cups of water, 1/1.2 cups of granulated sugar, and 4 cups of frozen ras

babunello [35]

We know that 16 cups are in 1 gallon
We also know that 10 servings = 2 cups

Now that means 80 servings = 1 gallon
That means we need 320 / 80=4

It is A 4 gallons
Hope this helps

3 0

3 years ago

Read 2 more answers

Ray created the list of factors for 48 below.

noname [10]

48 Is the answer that should be removed !

4 0

3 years ago

Read 2 more answers