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3 years ago

Solve the equation 2x^2 + 4x - 39 to the nearest tenth.

Mathematics

1 answer:

Virty [35]3 years ago

8 0

Answer:

cant be solved, when you try to you get

-1+78 = 77

which is

77 = 77

1=1

So cannot be factored

Step-by-step explanation:

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What is the force of a baseball that has a mass of 10 kg and has an acceleration of 30 m/s squared?

shepuryov [24]

Answer:

the force of the baseball is 300 N

4 0

3 years ago

Hi, does anyone know how to answer this?

satela [25.4K]

Answer:

Step-by-step explanation:

8 0

2 years ago

A very large tank initially contains 100L of pure water. Starting at time t = 0 a solution with a salt concentration of 0.8kg/L

Scorpion4ik [409]

Answer:

1. $\dfrac{dy}{dt}=4-\dfrac{3y(t)}{100+2t}$

2. $y(40) = 110.873 \ kg$

Step-by-step explanation:

Given that:

A very large tank initially contains 100 L of pure water.

Starting at time t = 0 a solution with a salt concentration of 0.8kg/L is added at a rate of 5L/min.

. The solution is kept thoroughly mixed and is drained from the tank at a rate of 3L/min.

As 5L/min is entering and 3L/min is drained out, there is a 2L increase per minute. Therefore, the amount of water at any given time t = (100 +2t) L

t = (50 + t ) L

Since it is given that we should consider y(t) to be the amount of salt (in kilograms) in the tank after t minutes.

Then , the differential equation that y satisfies can be computed as follows:

$\dfrac{dy}{dt}=rate_{in} - rate_{out}$

$\dfrac{dy}{dt}=(0.8)(5) -\dfrac{y(t)}{100+2t} \times3$

$\dfrac{dy}{dt}=(0.8)(5) -\dfrac{3y}{100+2t}$

$\dfrac{dy}{dt}=4-\dfrac{3y(t)}{100+2t}$

How much salt is in the tank after 40 minutes?

So,

suppose : $e^{\int \dfrac{3}{100+2t} \ dt} = (t+50)^{3/2}$

Then ,

$( t + 50)^{3/2} y' + \dfrac{3}{2}(t+50)^{1/2} y = 4(t+50)^{3/2}$

$( t + 50)^{1.5} y' + \dfrac{3}{2}(t+50)^{0.5} y = 4(t+50)^{3/2}$

$[y\ (t + 50)^{1.5}]' = 4(t+ 50)^{1.5}$

Taking the integral on both sides; we have:

$[y(t + 50)^{1.5}] = 1.6 (t + 50)^{2.5} + C$

$y = 1.6 (t+50)+C(t+50)^{-1.5}$

$y(0) = 0 = 1.6(0+50) + C ( 0 + 50)^{-1.5}$

$0 = 1.6(50) + C ( 50)^{-1.5}$

$C= -1.6(50)^{2.5}$

$y(40) = 1.6 (40 + 50)^1 - 1.6 (50)^{2.5}(50+40)^{-1.5}$

$y(40) = 144 - 1.6 \times 17677.66953 (90)^{-1.5}$

$y(40) = 144 - 1.6 \times 17677.66953 \times 0.001171213948$

$y(40) = 144 - 33.12693299$

$y(40) = 110.873 \ kg$

6 0

4 years ago

A membership to Movie Night Movie Club costs $10, plus $2 per movie. y = 2x +10. Use x-values: 0, 5, and 10.

Bumek [7]

Answer:

$10, $20, $30

Step-by-step explanation:

So, the equation you have set up already, y = 2x + 10, models the cost of the membership and movies, with y as the total cost, and x as the number of movies. Here we can just plug in the x values to get the total costs. If x is 0, we get $10 total, if it is 5, we get $20 total, and if it is 10, we get $30 total.

8 0

3 years ago

Read 2 more answers

CAN SOMEONE HELP ME PLEASE!!!

garik1379 [7]

$t^2 - 75 = 0$

Add 75 to the other side to isolate the $t^2$

$t^2 = 75$

Take the square root of both sides to cancel out the $t^2$

$\sqrt{t^2} = \sqrt{75}$

t = 8.6602540

I'd round it.

t = 8.7

6 0

3 years ago