Answer:
tubol mo mabaho kaya 1 too 5 so it means 5 days ka sa cr nag tutubol, ok <u>i</u><u> </u><u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>its</u><u> </u><u>the</u><u> </u><u>grett</u><u> </u><u>answer</u><u> </u><em> </em><em>do</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>your</em><em> </em><em>solution</em><em> </em><em>paper</em><em> </em><em>or</em><em> </em><em /><em>computers</em>
Normal body temperature
= 98.5 °F
Temperature falls by 3.5 °F during hypothermia
Hence there is a decrease in the normal temperature
Therefore the temperature during hypothermia
= 98.5 -3.5
= 95 °F
Answer:
h, negative, negative
Step-by-step explanation:
In this question, a piece-wise function is asked to be graphed.
Piece-wise function:
A piece-wise function is a function that has different definitions, depending on the input.
In this question, the function has three different definitions:
For x between -1(inclusive) and 0, y takes a constant value of -1.
For x between 0(inclusive) and 1, y takes a constant value of -2.
For x between 1(inclusive) and 2, y takes a constant value of -3.
Additionally:
At the inclusive points, the interval is circled, and thus, the graphic is given at the end of this answer.
For another example of the graphic of a piece-wise function, you can check brainly.com/question/16855064
Answer:
A) 1
B) 1
C) 0
Step-by-step explanation:
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes
We solve this question using the z score formula
z = (x-μ)/σ/√n, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
n = number of random samples
A) Less than 10 minutes
x < 10
z = 10 - 8.2/ 1.5 / √49
z = 8.4
P-value from Z-Table:
P(x<10) = 1
B) Between 5 and 10 minutes
For x = 5 minutes
z = 5 - 8.2/ 1.5 / √49
z = -14.93333
P-value from Z-Table:
P(x = 5) = 0
For x = 10 minutes
z = 10 - 8.2/ 1.5 / √49
z = 8.4
P-value from Z-Table:
P(x = 10) = 1
The probability that the average time waiting in line for these customers is between 5 and 10 minutes
P(x = 10) - P(x = 5)
= 1 - 0
= 1
C) Less than 6 minutes
x < 6
z = 6 - 8.2/ 1.5 / √49
z = -10.26667
P-value from Z-Table:
P(x<6) = 0
