Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
Answer:
what is x?
Step-by-step explanation:
C. 100 because 500 times 0.04(decimal form of 4%) is 20. 20 times 5(years) is 100
Answer: ∠REA = 53°
Step-by-step explanation:
Since ∠BEA = 71°, set both angle measures equal to that.
2x + 5x + 8 = 71
Solve for x. First, combine like terms:
7x + 8 = 71
Then, subtract 8 from both sides:
7x = 63
Divide both sides by 7:
x = 9
Now, plug x into ∠REA:
∠REA = 5x + 8
∠REA = 5(9) + 8
∠REA = 45 + 8
∠REA = 53°
Hope this helps!
I hope this helps you
x^3= -8^3
x= -8
